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Tresset [83]
3 years ago
5

Krzysztof solved the quadratic equation $11x^2-44x-99=0$ by completing the square. In the process, he came up with the equivalen

t equation (x+r)^2 = s, where $r$ and $s$ are constants. What is $r+s$?
Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

r = -2

s = 13

Step-by-step explanation:

Given quadratic equation is,

11x² - 44x - 99 = 0

Divide this equation by 11,

x² - 4x - 9 = 0

x² - 2(2)x - 9 = 0

x² -2(2)x + 2² - 2² - 9 = 0

[x² - 2(2)x + 2²] - 4- 9 = 0

(x - 2)² - 13 = 0

(x - 2)² = 13

[x + (-2)]² = 13

By comparing this equation with  (x + r)² = s

Values of the constants r and s will be,

r = (-2) and s = 13

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
Alisiya [41]
The answer is <span>2(–4y + 13) – 3y = –29

Step 1: Express </span><span>x from the second equation
Step 2: Substitute x into the first equation:

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</span><span>2x – 3y = –29 
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Step 1: 
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Rearrange it to get x:         x = - 4y + 13

Step 2:
The first equation is:          2x – 3y = –29 
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Substitute x from the second equation into the first one:
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Step-by-step explanation:

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