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4 years ago

In the following figure, the value of x is____

Mathematics

1 answer:

zubka84 [21]4 years ago

7 0

Answer:

x ≈ 8.3 ( to the nearest tenth )

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos41° = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{x}{11}$

Multiply both sides by 11

11 × cos41° = x, thus

x ≈ 8.3

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If f(x) = 6 what is x?

Margarita [4]

Answer:well you don't have x because x would be 1

5 0

3 years ago

Raina drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 6 hours. When Raina drove

Nostrana [21]

Answer: Raina's distance from the mountains is 176 miles

Step-by-step explanation:

Let x represent her average rate on the trip to the mountains.

If her average rate was 22 miles per hour faster on the trip home, it means that her average rate on the trip home is (x + 22) mph

Distance = speed × time

There was heavy traffic on the way there, and the trip took 6 hours. This means that the distance on her way to the mountain is 6x

When Raina drove home, there was no traffic and the trip only took 4 hours. This means that the distance on her way to home is

4(x + 22)

Since the distance covered is the same, then

6x = 4(x + 22) = 4x + 88

6x - 4x = 88

2x = 88

x = 88/2

x = 44

Raina's distance from the mountains is

6 × 44 = 176 miles

6 0

3 years ago

What is the product?<br><br> (6 r minus 1)(negative 8 r minus 3)

just olya [345]

Answer:

The required product is $-48r^2-10r+3$

Step-by-step explanation:

Consider the provided expression.

$(6r-1)(-8r-3)$

Open the parentheses.

$6r\left(-8r\right)+6r\left(-3\right)+\left(-1\right)\left(-8r\right)+\left(-1\right)\left(-3\right)$

$-6\cdot \:8rr-6\cdot \:3r+1\cdot \:8r+1\cdot \:3$

$-48r^2-18r+8r+3$

Add the like terms.

$-48r^2-10r+3$

Hence, the required product is $-48r^2-10r+3$

3 0

4 years ago

Read 2 more answers

5.Find the roots of the parabola given by the following equation.

snow_tiger [21]

Answer:

Part 5) The roots are x=-3 and x=1.5

Part 6) The solution on a number line is the shading area below of the line y=-1/3 (close circle)

Step-by-step explanation:

Part 5) Find the roots of the parabola given by the following equation

$2x^{2} +5x-9=2x$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^{2}+5x-2x-9=0$

$2x^{2}+3x-9=0$

$a=2\\b=3\\c=-9$

substitute in the formula

$x=\frac{-3(+/-)\sqrt{3^{2}-4(2)(-9)}} {2(2)}$

$x=\frac{-3(+/-)\sqrt{81}} {4}$

$x=\frac{-3(+/-)9} {4}$

$x=\frac{-3(+)9} {4}=1.5$

$x=\frac{-3(-)9} {4}=-3$

therefore

The roots are x=-3 and x=1.5

Part 6) Solve the inequality and graph the solution on a number line.

$-3(5y-4)\geq 17$

Solve for y

$-15y+12\geq 17$

Subtract 12 both sides

$-15y\geq 17-12$

$-15y\geq 5$

Multiply by -1 both sides

$15y\leq -5$

Divide by 15 both sides

$y\leq -1/3$

The solution is the interval -----> (-∞, -1/3]

All real numbers less than or equal to negative one third

The solution on a number line is the shading area below of the line y=-1/3 (close circle)

The graph in the attached figure

7 0

3 years ago

Solve for x:-2(x+3)=-2(x+1)-4

strojnjashka [21]

Answer:

x is any real number

Step-by-step explanation:

The simplified form of the equation is ...

-2x -6 = -2x -2 -4

-2x -6 = -2x -6 . . . . . . . . true for any x

x is any real number.

___

The equation effectively resolves to 0x=0, which will always be true for any value of x.

3 0

3 years ago