There are two possible outcomes of this experiment either success p or failure q. It has a given number of trials and all trials are independent therefore it is<u><em> binomial probability distribution.</em></u>
1- 5 ways
2- 5/16
3- 1/16
4- 1/16
In the question given above n= 5 p =1/2 q= 1/2 r is the given point.
- <u>Part 1:</u>
The number of ways in which different people get off the bus can be calculated using combinations since the order is not essential. Therefore
nCr= 5C4= 5 ways
<u>2. Part 2:</u>
The probability that all four people get off the bus on the first stop is given by :
P (x= 1)= 5C1 (1/2)^0(1/2)^4= 5(1/2)^4= 5/16
<u>3. Part 3:-</u> The probability that all four people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^0(1/2)^4= 1(1/2)^4= 1/16
<u>4. Part 4-</u> The probability that <u><em>exactly three of the four</em></u> people get off the bus on the same stop.
P (x= x)= 5C5 (1/2)^3(1/2)^1= 1(1/2)^4= 1/16
For binomial distribution click
brainly.com/question/15246027
brainly.com/question/13542338
<span>1000 meters per second is the answer
radius =25.23Km
(t)= days
</span>
Answer:
113.26087 as a fraction equals 11326087/100000
Step-by-step explanation:
To write 113.26087 as a fraction you have to write 113.26087 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
113.26087 = 113.26087/1 = 1132.6087/10 = 11326.087/100 = 113260.87/1000 = 1132608.7/10000 = 11326087/100000
For this case we have that the main function is given by:
We apply the following transformations:
Vertical expansions:
To graph y = a * f (x)
If a> 1, the graph of y = f (x) is expanded vertically by a factor a.
For a = 5 we have:
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units up.
For k = 5 we have:
Answer:
The graph of g (x) is the graph of f (x) stretched vertically by a factor of 5 and translated up 5 units.
Step-by-step explanation:
part A:
ABCD is transformed to obtain figure A′B′C′D′:
1) by reflection over x-axis, obtain the image :
A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)
2) by translation T (7 0), obtain the image :
A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)
part B:
the two figures are congruent.
the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)
