The area of ΔIDK is 32.69 square units.
Solution:
Given data:
ID = 7 and Hypotenuse, KI = 11.67.
Let us first find KD:
Using Pythagoras theorem,
Subtract 49 from both sides.
Taking square root on both sides, we get
KD = 9.34
Area of the triangle = 
= 32.69
The area of ΔIDK is 32.69 square units.
Answer:
7
Step-by-step explanation:
(12 * 7 + n)8=12.5
(12 * 7 + n)= 100
N= 16. The new number will be 16. Hope this helps. :)
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
