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diamong [38]
3 years ago
11

A square field has an area of 9,604 square yards. How long is each side of the field

Mathematics
1 answer:
Dominik [7]3 years ago
6 0

Answer:

2,401 yards long

Step-by-step explanation:

9,604 divided by 4 = 2,401

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Hi guys, Can anyone help me with this tripple integral? Thank you:)
OleMash [197]

I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.

We have to turn K into the limits of integration on our integrals.

Clearly 0 is the lower limit for all three of x, y and z.

Now we have to incorporate

x+y+z ≤ 1

Let's do the outer integral over x.  It can go the full range from 0 to 1 without violating the constraint.  So the upper limit on the outer integral is 1.

Next integral is over y.  y ≤ 1-x-z.   We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y.  So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.

Similarly the inner integral goes from z=0 to z=1-x-y

We've transformed our integral into the more tractable

\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx

For the inner integral we get to treat x like a constant.

\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3

Let's expand that as a polynomial in y for the next integration,

= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3

The middle integration is

\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy

= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x}

= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3

Expanding, that's

=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)

so our outer integral is

\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).

= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12

=0

That's a surprise. You might want to check it.

Answer: 0

6 0
3 years ago
At the movie theatre, child admission is $5.20 and adult admission is $9.00 . On Saturday, 156 tickets were sold for a total sal
stiks02 [169]

We can solve this by using systems of equations.

Let's find our first formula, how much money was made using the tickets.

5.20x + 9y = 1027.80

Here x is how many child tickets we sold and y is how many adult tickets we sold. Now that we have defined that, we can make another formula for the total tickets sold!

x + y = 156 since we sold 156 tickets that could be any combination of child and adult tickets.

Let's solve this system. I'm going to use <em>substitution</em> so I'm going to take our second formula and subtract both sides by x to get y = 156 - x.

Now I will plug this in the first equation for y to get You plug it in for y to get 5.20x + 9 (156-x) = 1027.8.

From this you can solve for x to get x = 99.

Since x + y = 156

99 + y = 156

y = 57

There were 99 child tickets and 57 adult tickets.

3 0
3 years ago
-5x+4y=3<br><br> x=2y-15<br><br><br> Solve for y and x
serious [3.7K]

Answer:

<em><u>x=9, y=12</u></em>

Step-by-step explanation:

-5x+4y=3 --------A

x=2y-15----------B

Putting the value of x from B in A

-5(2y-15) +4y=3

-10y+75+4y=3

-6y=3-72

-6y=-72

y=72/6= 12

Putting the value of y =12 in B

x= 2(12)-15

x= 24-15

x=9

3 0
3 years ago
Can someone pls help me<br> Pls
lora16 [44]

Answer:

help u with what? Say what u need

5 0
3 years ago
Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 20
m_a_m_a [10]

Answer:

\text{Net accrual income}=\$31,600

Step-by-step explanation:

We have been given that Marigold Industries collected $104,000 from customers in 2019. Of the amount collected, $24,400 was for services performed in 2018. In addition, Marigold performed services worth $39,000 in 2019, which will not be collected until 2020.

Let us find revenue earned in 2019 by subtracting revenue earned from 2018 and adding revenue earned in 2019 to total revenue as:

\text{Revenue in 2019}=\$104,000-\$24,400+\$39,000

\text{Revenue in 2019}=\$118,600

Marigold Industries also paid $73,900 for expenses in 2019. Of the amount paid, $29,100 was for expenses incurred on account in 2018. In addition, Marigold incurred $42,200 of expenses in 2019, which will not be paid until 2020.

Now, we will find expenses in 2019 by subtracting expenses in 2018 and adding expenses in 2019 to total expenses as:

\text{Expenses in 2019}=\$73,900-\$29,100+\$42,200

\text{Expenses in 2019}=\$87,000

To find accrual net-income, we will subtract$87,000 from $118,600 as:

\text{Net accrual income}=\$118,600-\$87,000

\text{Net accrual income}=\$31,600

Therefore, the net accrual income for 2019 would be $31,600.

5 0
3 years ago
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