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stira [4]
3 years ago
6

Write an equation for the parabola whose vertex is at (4, 9) and which passes through (5, 24).

Mathematics
1 answer:
babunello [35]3 years ago
8 0
The general formula to form a parabole equation is written below.
y = a(x - h)² + k
with (x,y) is one of the points lies on the parabola, and (h,k) is the vertex of the parabola.

From the question above, we get this information
(x,y) = (5,24)
(h,k) = (4,9)
The remaining value to find is a. We need to find the value of a to form the equation. Input the numbers to the equation.
y = a(x - h)² + k
24 = a(5 - 4)² + 9
24 = a(1) + 9
24 = a + 9
24 - 9 = a
a = 15

Write the equation, without inputing the value of x and y
y = a(x - h)² + k
y = 15(x - 4)² + 9
<em>This is the equation</em>
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Answer:

Their lines never touch. They have 2 different sides. They are like a square but differen. They always have even number.

Step-by-step explanation:

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3 years ago
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Find the range of y = -3x + 7 for the domain {-8, -6, -3, -2, 2}
svetlana [45]
The domain is the set of x-values of a function. The range is the set of y-values of a function.

You are told that the domain, or x-values, are -8, -6, -3, -2, and 2. To find the range, you just need to plug in each of the x-values into the function <span>y = -3x + 7 and find the value of y.
1) When x = -8:
</span><span>y = -3x + 7
y = -3(-8) + 7
y = 24 + 7
y = 31

2) When x = -6
</span>y = -3x + 7
y = -3(-6) + 7
y = 18 + 7
y = 25

3) When x = -3
y = -3x + 7
y = -3(-3) + 7
y = 9 + 7
y = 16

4) When x = -2
y = -3x + 7
y = -3(-2) + 7
y = 6 + 7
y = 13

5) When y = 2
y = -3x + 7
y = -3(2) + 7
y = -6 + 7
y = 1

The range is {31, 25, 16, 13, 1}.

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Answer: 
{31, 25, 16, 13, 1}
5 0
3 years ago
A delivery fee for tuber eats was 10
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3 years ago
The composite shape is made up of two identical triangles and two different rectangles. What is the are of the composite shape i
AfilCa [17]

Answer: 72 u^2

<h3>Explanation:</h3>

What we know:

  • Both triangles are identical
  • Both rectangles are different
  • There are values in units^2 given
  • There are right angles

How to solve:

We need to find the area of at least one of the triangles and double it. Then, we need to find the areas of both rectangles. Finally, we need to add these areas to find the total area. The final area will be represented in units squared (u^2)

<h2>Process:</h2>

Triangles

Set up equation                                                 A = 1/2(bh)

Substitute                                                           A = 1/2(4*3)

Simplify                                                               A = 1/2(12)

Solve                                                                   A = 6

Double                                                                     *2

                                                                           A = 12 u^2

Rectangles

Set up equation                                                 A = lh

Substitute                                                           A = (14)(3)

Simplify                                                               A = 42 u^2

Set up equation                                                 A = lh

Substitute                                                           A = [14-(4+4)](3)

Simplify                                                               A = (14-8)(3)

Simplify                                                               A = (6)(3)

Multiply                                                               A = 18 u^2

Total Area

Set up equation                                                 A = R1+R2+T

Substitute                                                           A = 42 + 18 + 12

Simplify                                                               A = 60 + 12

Solve                                                                   A = 72 u^2

<h3>Answer: 72 u^2</h3>
4 0
2 years ago
Y = -1<br> 4x + 3y = -19
lubasha [3.4K]
I got 4x-3=-19 then I got stuck

7 0
2 years ago
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