Answer: option D
Step-by-step explanation:
Remember the cosine identity:
Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:
Now you can substitute values into and then reduce the fraction.
THerefore you get:
Answer:
just do 19.60/20 = 0.98$/lbs
hope that answers your question
Step-by-step explanation:
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
General Idea:
The Rules for Transformations of Functions are given below:
If f(x) is the original function, a > 0 and c > 0; Then
Applying the concept:
In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:
C.it stretches the graph vertically by a factor of 5
If p(x) is a function, then a real-world example might be
The amount of fish food, in grams required for the giant koi fish in the pond can be represented by the function
. If there are 50 fish, how many grams of fish food will you need?
