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avanturin [10]
3 years ago
12

Plot the fraction 7/ 12 on the number line . Is 7/12 closer to 0, 1/2, or 1?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:

7/12 is closer to 1/2

Step-by-step explanation:

6/12=1/2

12/12=1

0/12=0

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What is the cosine of angle F <br><br>A. 4/5<br>B. 3/4<br>C. 5/4<br>D. 3/5​
saveliy_v [14]

Answer: option D

Step-by-step explanation:

Remember the cosine identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

adjacent=15\\hypotenuse=25

Now you can substitute values into  cos\alpha=\frac{adjacent}{hypotenuse} and then reduce the fraction.

THerefore you get:cos(F)=\frac{15}{25}\\\\cos(F)=\frac{3}{5}

6 0
3 years ago
Read 2 more answers
A 20-pound bag of fertilizer costs $19.60. What is the cost<br> per pound?
Sladkaya [172]

Answer:

just do 19.60/20 = 0.98$/lbs

hope that answers your question

Step-by-step explanation:

3 0
3 years ago
Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm t
Angelina_Jolie [31]
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
3 0
3 years ago
In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0

f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

4 0
3 years ago
Read 2 more answers
What is a real world word problem for 57.5=p(250)
sladkih [1.3K]
If p(x) is a function, then a real-world example might be

The amount of fish food, in grams required for the giant koi fish in the pond can be represented by the function p(f)=\frac{f}{50} +7.5. If there are 50 fish, how many grams of fish food will you need?

p(250)=\frac{250}{50} +7.5
p(250)=50 +7.5
p(250) = 57.5
3 0
3 years ago
Read 2 more answers
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