Answer:
Should be 1 if im not wrong Then Mark Me brainliest
Step-by-step explanation:
a negative times a neg equals a posative
Neg x pos = neg
pos x neg = neg
pos x pos = pos
neg x neg = pos
so if there greater then over neg<, >,=
You would look at the problem for given f(x)=
x → -1 and neg times neg more or less
-1 x -1 = 1
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
Answer:
-1952
Step-by-step explanation:
Answer:
2 3/4
Step-by-step explanation:
Answer:
The choice C.94
Step-by-step explanation:
