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irga5000 [103]
2 years ago
15

Tim had $150 to spend on 3 pairs of pants. After buying

Mathematics
1 answer:
Gala2k [10]2 years ago
7 0
D) 3x + 30 = 150, hope this helps!
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Gennadij [26K]

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Step-by-step explanation:

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PLSSS HELP IF YOU TURLY KNOW THISS
xxTIMURxx [149]

Answer:

2m+4 is the answer

Step-by-step explanation:

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Find the length of LM if L is the midpoint of NM. NL = 3x + 1, LM = 8x - 24.
SashulF [63]

Answer:

LM = 16

Step-by-step explanation:

From the question given:

L is the midpoint of NM

NL = 3x + 1

LM = 8x - 24

LM =?

Next, we shall determine the value of x.

This can be obtained as follow:

Since L is the midpoint of NM, it means that NL and LM are equal i.e

NL = LM

Thus, we can obtain the value of x as follow:

NL = 3x + 1

LM = 8x - 24

NL = LM

3x + 1 = 8x - 24

Collect like terms

3x - 8x = - 24 - 1

-5x = - 25

Divide both side by - 5

x = -25/-5

x = 5

Finally, we shall determine the length of LM as follow:

LM = 8x - 24

x = 5

LM = 8(5) - 24

LM = 40 - 24

LM = 16

Therefore, the length of LM is 16

8 0
3 years ago
A master student is planning to take a qualifying exam in the coming summer. She has three chances. The first one is in June. If
Soloha48 [4]

Answer:

Step-by-step explanation:

Given

P_1=Probability of clearing exam in 1 st attempt=0.5

P_2=Probability of clearing exam in 2 nd attempt=0.7

P_3=Probability of clearing exam in 3 rd attempt=0.8

Probability that she passes the exam=P(1 st\ attempt)+P(1\ fail)\cdot P(2\ pass)+P(1\ fail)\cdot P(2\ fail)\cdot P(3 rd pass)

P=0.5+0.5\times 0.7+0.5\times 0.3\times 0.8=0.97

(b)P(Pass qualification on 2nd try|passes qualification)

P(Pass qualification on 2nd try|passes qualification)=\frac{P(fail\ on\ 1 )\cdot P(pass\ in\ 2nd)}{P(passes)}

P(Pass qualification on 2nd try|passes qualification)=\frac{0.5\times 0.7}{0.97}=0.3608

5 0
3 years ago
On rainy days, Izzy goes from his house to the school by running 1.2 miles on West St, then makes a 90º turn and runs 0.5 miles
OlgaM077 [116]

Answer:

a) It will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.

b) Izzy runs 1.30 miles on dry days.

c) Izzy saves 3 minutes and 12 seconds cutting through the woods.

Step-by-step explanation:

This problem can be solved by a simpe rule of three problem.

a) On rainy days, she runs 1.2 + 0.5 = 1.7 miles.

The problem states that for rainy days, she runs 7.5 miles per hour. We know that in a hour, Izzy will run 7.5 miles. We want to know how long it takes for her to run 1.7 miles. So

1 hour - 7.5 miles

x hours - 1.7 miles

7.5x = 1.7

x = \frac{1.7}{7.5}

x = 0.226 hours

It will take Izzy 0.226 hours = 13.6 minutes = 13 minutes 36 seconds to run to school on dashed days.

b) Now we have a right triangle, where the sides are the 1.2 miles and the 0.5miles, and the path through the woods x is the hypotenuse.

So, we apply the pythagorean theorem.

x^{2} = (1.2)^{2} + (0.5)^{2}

x^{2} = 1.44 + 0.25

x^{2} = 1.69

x = 1.30

So, Izzy runs 1.30 miles on dry days.

c) The first step for this question is knowing how long it takes for Izzy to run 1.30 miles at 7.50 miles a hour. So:

1 hour - 7.50 miles

x hours = 1.30 miles

7.50x = 1.30

x = \frac{1.3}{7.5}

x = 0.173 hours

So, it takes Izzy 0.173 hours = 10.4 minutes = 10 minutes 24 seconds to run through the woods.

13' 36''

-10' 24''

3' 12''

Izzy saves 3 minutes and 12 seconds cutting through the woods.

5 0
3 years ago
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