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ArbitrLikvidat [17]
3 years ago
11

What is the smallest solution to the equation

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0

Answer:

The value of x is 6 and -6. The smallest value of x is -6

Step-by-step explanation:

2/3 x² = 24

solving this equation for finding the value of x.

Multiply both sides by 3/2

x² = 24 * 3/2

x² = 72/2

x² = 36

Now, to find the value of x taking square root on both sides

√x² = √36

x= ±6

So, the value of x is 6 and -6. The smallest value of x is -6

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5. A fruit concentrate is sold in 250 mL packs. The instructions are 'Add water to make one litre of ready-to-drink fruit juice'
Ierofanga [76]
Given ,

Concentrate= 250 mL

Water = 1 liter = 1000 mL

A) ratio is 250:1000 = 1:4

B) for 250 mL it is 1 liter now for 2000mL it is X .

=> x = 2000/250 = 8 liters

C) volume of water in 6L of made up juice is 1500 mL

D) 1 liter - 5 glasses

For 80 glasses it would be 80/5 = 16 glasses
4 0
2 years ago
How often does always never sometimes
Vanyuwa [196]

1) sometimes

2) always

3) always

8 0
2 years ago
A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

(\left {{20} \atop {2}} \right. )=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

(\left {{3} \atop {2}} \right. )=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

\frac{3}{190}\\ =0.01579\\=0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0
2 years ago
Need help please I will give brainlist
Vlad [161]

Answer:

it is c

Step-by-step explanation:

c

6 0
3 years ago
Read 2 more answers
Solve 3x - 6y = – 1 for y
umka2103 [35]

Answer:

Step-by-step explanation:

3x - 6y = -1

-6y = -1 -3x

-6y = -(1+3x)

   y = -(1+3x)/-6

y = (1 + 3x )/6

7 0
4 years ago
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