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il63 [147K]
3 years ago
5

WILL GIVE BRAINLIEST& 15 PTS.

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Igoryamba3 years ago
3 0
The answer to this question would be:


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Let's say is "x".

so, "x" is the whole or 10/10 whilst 0.002 is 1/10 then, let's check

\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
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\\\\\\
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Given:

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