Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
6 * 24 * 10 * 10 = 14,400
Step-by-step explanation:
6 * 10 = 60.
24 * 10 = 240.
60 * 240 = 14,400.
hope this helps.
B is the Y-intercept or where the graph crosses the y-axis. they provide you with a few things which can help you figure this out. they give you the values of x and y in a table
X | Y
2 | -5
4 | -9 The difference between each Y value is 4...so, I add 4 to the -5
6 | -13 and get -1...going up another value for the X would be at 0. This leaves me with an ordered pair of (0,-1).....thus, the value of b is -1.
Answer:
Step-by-step explanation:
Volume of pot = πr²h
= 3.14 * 10 * 10 * 20
= 6280 cubic cm
1000 cubic cm = 1 litre
6280 cubic cm = 6.28 litre
∵ 2.5 litres will fit in the pot as the capacity of pot is 6.28 litre
Answer:
Step-by-step explanation:
AC is the geometric mean. Solve it using this proportion:
Now fill in the values we know:
Cross multiply to get
That means that
AC = 
, which, in decimal form is
AC = 11.40175425
