Someone help me out please I can’t figure out this question

Mathematics

2 answers:

GaryK [48]3 years ago

5 0

Answer:

She should have added 3, not subtracted 3, to both sides

Step-by-step explanation:

this problem calls for the inverse of operations

$x-3=7\\\\\\3+x-3=7+3\\\\x=10$

Delvig [45]3 years ago

5 0

Answer:

She should have added 3, not subtracted, to both sides

Step-by-step explanation:

You're trying to get X by itself and to do that you need to add 3 to cancel out the -3.

You might be interested in

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

Download xls