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2 years ago

Someone help me out please I can’t figure out this question

Mathematics

2 answers:

GaryK [48]2 years ago

5 0

Answer:

She should have added 3, not subtracted 3, to both sides

Step-by-step explanation:

this problem calls for the inverse of operations

$x-3=7\\\\\\3+x-3=7+3\\\\x=10$

Delvig [45]2 years ago

5 0

Answer:

She should have added 3, not subtracted, to both sides

Step-by-step explanation:

You're trying to get X by itself and to do that you need to add 3 to cancel out the -3.

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A function follows the rule y = -75 - 5 x . When the function's output is 25, the equation is 25 = -75 - 5 x .

zhenek [66]

Answer:

same here idek tbh

Step-by-step explanation:

.......

3 0

3 years ago

If the average(arithmetic mean) of 5 and r is 7 and the average of 3 and s is 3 , what is the average of r and s?

Norma-Jean [14]

Answer:

Step-by-step explanation:

Calculate the values of both r and s, that is

$\frac{5+r}{2}$ = 7 ( multiply both sides by 2 )

5 + r = 14 ( subtract 5 from both sides )

r = 9

and

$\frac{3+s}{2}$ = 3 ( multiply both sides by 2 )

3 + s = 6 ( subtract 3 from both sides )

s = 3

Hence

$\frac{9+3}{2}$ = $\frac{12}{2}$ = 6 → C

5 0

3 years ago

What is the y intercept of x=14

Sophie [7]

Answer:

Step-by-step explanation:

x=14 is a vertical line with undefined slope

It has no y intercept and has only x intercept of 14.

6 0

3 years ago

The radius of a large sphere is 8 times the radius of a small sphere. the surface area of the large sphere is how many times the

kondaur [170]

Large sphere's radius = R,
small sphere's radius = r, R = 8r
surface area of a sphere (SA) = 4×pi×radius^2
So what we need is the SA of the larger in terms of the smaller sphere, so if:
SA (of R) = 4×pi×R^2, then plug in "8r" for "R"...
SA = 4×pi×(8r)^2 = 4×3.14×64r^2
SA = 12.57×64r^2 = 804 r^2
Therefore the SA of the larger sphere is 804 times the SA of the smaller sphere.
I hope that makes sense!

8 0

3 years ago

9. Simran had some ₹2 and ₹ 5 coins.She exchanged them for ₹ 10 coins. If the number of ₹ 5 coins is one less than the number of

sertanlavr [38]

Answer:

Step-by-step explanation:

Let x be the number of 2 coins and y be the number of 5 coins. Let z be the number of 10 coins she exchanged. Then, we have the first equation

$2x+5y = 10z$

Since she has one 5 coin less than 2 coins, then y=x-1. So we get the equation

$2x+5(x-1) = 10z$

which is equivalent to

$7x-5 = 10z$

If we add 5 on both sides and factor out on the right by 5 we get

$7x = 5(2z+1)$

We can solve for x and get

$x = \frac{5(2z+1)}{7}$

Since x represents the number of 2 coins, we must have that x is an integer. That is, we cannot have, for example 1.5 2 coins. Since 7 doesn't divide 5, we must have that 7 divides 2z+1. That is, the value of z is such that the number 2z+1 is multiple of 7. That is 2z+1 = 7p where p is an integer.

If that is the case, then

x = 5p, then y = 5p-1. By having 2z+1 = 7p, we are forcing that p is an odd integer, so we have infinite solutions. For each value of p that is an odd integer, then x=5p and y=5p-1 is a solution to the problem

7 0

3 years ago