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bogdanovich [222]
3 years ago
15

Which of the following is equal to the expression below?

Mathematics
2 answers:
azamat3 years ago
8 0

Answer:

8\sqrt[3]{(5)}

Step-by-step explanation:

We have been given an expression (8\times 320)^{\frac{1}{3}. We are asked to find which expression of given expressions is equal to our given expression.

Using exponent property (a)^{\frac{m}{n}}=\sqrt[n]{a^m} we can rewrite our given expression as:

\sqrt[3]{(8\times 320)^1}

\sqrt[3]{(8\times 320)}

Rewriting 320 as 64\times 5 in our given expression we will get,

\sqrt[3]{(8\times 64\times 5)}

\sqrt[3]{(2^3\times 4^3\times 5)}

Pulling our 2 and 4 from cube root we will get,

2\times 4\sqrt[3]{(5)}

8\sqrt[3]{(5)}

Therefore, the expression 8\sqrt[3]{(5)} is equal to our given expression and option D is the correct choice.

aliina [53]3 years ago
6 0

(8 x 320)^1/3

(2560)^1/3

(64*40)^1/3

64^1/3   *40^1/3

4 * (8^1/3) * 5^1/3

4 * 2 * 5^1/3

8 *5^1/3

None of your choices are written correctly

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880,005 rounded to the nearest hundred thousand is
MrMuchimi

Answer:

900,000

Step-by-step explanation:

It's so easy. Don't need to explain.

4 0
3 years ago
Read 2 more answers
The graph below shows the solution to which system of inequalities?
nlexa [21]

Answer:

Option D.

Step-by-step explanation:

Consider option D. y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3

Take point (0,0)

On putting this point in inequation y\leq \frac{3x}{4}+10 , we get

0\leq 10 which is true . So, solution is region towards the origin i,e region below the line y= \frac{3x}{4}+10 including the line itself .

On putting (0,0) in inequation y\leq \frac{-x}{2}-3 , we get 0\leq -3 which is false , so solution is region away from the origin i.e region below line y= \frac{-x}{2}-3 including the line itself .

So, common solution to both the inequations is the shaded part in the given figure .

In other words, we can say that the graph shown in the given figure represents system of equations: y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3

5 0
3 years ago
I NEED HELP ASAP!!!!
ycow [4]

Answer:

I think it is the fort

h one as well I might be wrong tho I'm only in 6th grade...

Step-by-step explanation:

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7 0
2 years ago
Give an example of this when adding two rationalnumbers with different signs and provide the product.
kolezko [41]

ANSWER:

\begin{gathered} \frac{4}{5}+-\frac{8}{3}=-\frac{28}{15} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{32}{15} \end{gathered}

STEP-BY-STEP EXPLANATION:

Rational numbers are all numbers that can be expressed as a fraction, that is, as the quotient of two whole numbers.

Therefore, an example would be:

\begin{gathered} \frac{4}{5}\text{ and - }\frac{8}{3} \\ \text{adding} \\ \frac{4}{5}+-\frac{8}{3}=\frac{4}{5}-\frac{8}{3} \\ \frac{4}{5}-\frac{8}{3}=\frac{4\cdot3-5\cdot8}{5\cdot3}=\frac{12-40}{15}=-\frac{28}{15} \\ \text{ product} \\ \frac{4}{5}\cdot-\frac{8}{3}=-\frac{4\cdot8}{5\cdot3}=-\frac{32}{15} \end{gathered}

5 0
1 year ago
What is the equation, in standard form, of a parabola that models the values in the table?
love history [14]

Answer:

<u>Y=4x^2+3x-6</u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u>Y=3x^2+4x-6 for (-2,4)</u>

Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\

This does not give 4 as the answer and is not a solution.

<u>Y=4x^2+3x-6 for (-2,4)</u>

Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\

This does give 4 as the answer and is a possible solution.

<u>Y=4x^2-3x-6 for (-2,4)</u>

Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\

This does not give 4 as the answer and is not a solution.

<u>Y=-4x^2-3x-6 for (-2,4)</u>

Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\

This does not give 4 as the answer and is not a solution.

The only possible solution is <u>Y=4x^2+3x-6</u>

3 0
3 years ago
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