Answer:
Perimeter of rectangle 1=4x+4
Perimeter of rectangle 2=4x+4
Step-by-step explanation:
Two squares with the same dimension
Square 1: let length=x
Square 2: let length=x
Since they have same dimensions
He added two inches to the length of square 1 to make it a rectangle
Rectangle 1: width=x, length=x+2
Perimeter=2(l+w)
=2{(x+2)+x}
=2(x+2+x)
=2(2x+2)
=4x+4
He added two inches to the width of square 2 to make it a rectangle
Rectangle 2: length=x, width=x+2
Perimeter=2(l+w)
=2{(x+(x+2)}
=2(x+x+2)
=2(2x+2)
=4x+4
The two rectangles have equal perimeter
