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Tom [10]
2 years ago
12

Please help on questions 8&9!!!!(higher maths vectors)

Mathematics
1 answer:
alekssr [168]2 years ago
4 0
How are we supposed to draw a diagram for you? do you want me to explain to you how to answer the question?
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38,503 rounded to the nearest ten thousand
skad [1K]

Answer:

39,000

Step-by-step explanation:

8 0
2 years ago
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I cant understand this hepl me help me
Aleonysh [2.5K]

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A

Step-by-step explanation:

7 0
3 years ago
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The fishbowl is shaped like a sphere the fishbowl has a diameter of 16 what is the closest value of water in the Fishbowl and cu
katovenus [111]

Answer:

2144.66 cubic inches

Step-by-step explanation:

The fishbowl is shaped like a sphere the fishbowl has a diameter of 16.

What is the closest value of water in the Fishbowl in cubic inches?

From the any question, we were told to find the closest value of the water in the fishbowl in cubic inches.

This means we are to find the volume.

The volume of a sphere is given as:

4/3πr³

We are given Diameter of the fish bowl = 16 inches

Radius = Diameter/2 = 16 inches/2

= 8 inches

Hence,

Volume of the sphere (Volume of water) = 4/3 × π × 8³

= 2144.66 cubic inches

3 0
3 years ago
Let $f(x)$ be a function defined for all positive real numbers satisfying the conditions $f(x) > 0$ for all $x > 0$ and $f
algol [13]
Suppose we choose x=1 and y=\dfrac12. Then

f(x-y)=\sqrt{f(xy)+1}\implies f\left(\dfrac12\right)=\sqrt{f\left(\dfrac12\right)+1}\implies f\left(\dfrac12\right)=\dfrac{1+\sqrt5}2


Now suppose we choose x,y such that

\begin{cases}x-y=\dfrac12\\\\xy=2009\end{cases}


where we pick the solution for this system such that x>y>0. Then we find

\dfrac{1+\sqrt5}2=\sqrt{f(2009)+1}\implies f(2009)=\dfrac{1+\sqrt5}2

Note that you can always find a solution to the system above that satisfies x>y>0 as long as x>\dfrac12. What this means is that you can always find the value of f(x) as a (constant) function of f\left(\dfrac12\right).
3 0
3 years ago
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What two numbers add up to 6.5 and multiply to .64
melomori [17]
You multiply by 10 or more
5 0
2 years ago
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