Answer:
1. C-surface area
2. The formula V = B x h is not suitable, because the surface area of wrapping paper needed to be calculated, not the volume.
V = Ph + 2B = 15x(5+6+9) + 2x 9x3/2 = 327
3. B: Base area
H: Height of solid
4. She said V =220, while V_real = 7x6x4 =168
=> She is wrong
5. Check the Pythagorean theorem 3^2+4^2 =9+16 =25 =5^2
=> Right triangle.
=> Area = 3x4/2 =6
Answer:
2
Step-by-step explanation:
we start simplifying by removing the parenthesis
Multiply the exponents inside the the parenthesis
3^4 * 2^4
Now we apply exponential property
a^m * a^n = a^ (m+n)
3^4 * 3^-3 = 3^ (4-3) = 3^1
3 or 3^1 are same
3^1 at the top and bottom so we cancel it out
\frac{2^4}{2^3}
we apply log property . a^m / a^n = a^m-n
Now subtract the exponents
2^(4-3) = 2^1 = 2
Answer:
-5
Step-by-step explanation:
Answer:
- sin(θ) = -(4√15)/17
- cos(θ) = 7/17 . . . . . . . given
- tan(θ) = -(4√15)/7
- csc(θ) = -(17√15)/60
- sec(θ) = 17/7
- cot(θ) = -(7√15)/60
Step-by-step explanation:
The relationship between sine and cosine is ...
sin² + cos² = 1
Solving for sine gives ...
sin = ±√(1 -cos²)
In this problem, we want the negative root.
sin(θ) = -√(1 -(7/17)²) = -√(240/289) = -(4√15)/17
tan(θ) = sin(θ)/cos(θ) = ((-4√15)/17)/(7/17) = -(4√15)/7
___
And the inverse functions are ...
sec(θ) = 1/cos(θ) = 17/7
csc(θ) = 1/sin(θ) = -17/(4√15) = -(17√15)/60
cot(θ) = 1/tan(θ) = -(7√15)/60
_____
Of course, you're aware that 1/√15 = (√15)/15.
