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Ksivusya [100]
3 years ago
12

Solve for unknown angles using algebra

Mathematics
1 answer:
kozerog [31]3 years ago
8 0
Jsh xhj d xja extra d best of the first☝☝☝☝ can you please don't have HD for you just like the first day
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Find all the real zeros of x3-2x2-5x+6=0.
WITCHER [35]
(×-1)(×-3)(×+2)
×=1
×=3
×=-2

×1=-2
×2=1
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3 0
3 years ago
The LCM of three numbers is 7920 and their GCD is 12. Two of the numbers are 48 and 264. Using factor notation find the third nu
12345 [234]

Answer:

The third number is 180.

Step-by-step explanation:

Let the third number be 9x where x is an integer.

48 = 2*2*2*2*3

264 = 2*2*2*3*11

9x = 3*3*x

2*2*2*2*3*3*11*x = 7920y where y is an integer

1584x = 7920y

so x = 7920y / 1584= 5y.

Now the GCD is 12  so x must have  4 as one of its factors.

Also x is a multiple of 5 so it could be 20 then y  would be 4.

If x = 20 then the third number is 9*20 = 180.

This checks out OK.

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3 years ago
Situation: You land your dream job. You negotiate a starting salary of $50,500. You are told that you will get a 6% increase in
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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If (6^0)^x= 1 what are the possible outcomes of x? Explain your answer.
swat32
X can be any  real number 

As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.

As stated by WojtekR, even negative numbers can get 1

x = - 5

(6^0)^-5 =  1^-5 = 1/1 = 1


~ Thanks @WojtekR
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3 years ago
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