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AlladinOne [14]
3 years ago
9

Question 3

Mathematics
2 answers:
Sav [38]3 years ago
6 0

Answer:

In order for line AE to equal line BF, m/DFB and m/CEA must both be 90°. When this occurs, line AB does not intersect line EF: the two lines are parallel. line AE and line BF represent the perpendicular distances between line AB and line CD. When the two lines are parallel, the perpendicular distance between them is the same throughout their length.

Step-by-step explanation:

sample answer from question.

andriy [413]3 years ago
6 0

Answer:

In order for line AE to equal line BF, m/DFB and m/CEA must both be 90°. When this occurs, line AB does not intersect line EF: the two lines are parallel. line AE and line BF represent the perpendicular distances between line AB and line CD. When the two lines are parallel, the perpendicular distance between them is the same throughout their length.

Step-by-step explanation:

Plato Sample Question

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Kevin and his children went into a restaurant and he bought $31.50 worth of hotdogs and drinks. Each hotdog costs $4.50 and each
Musya8 [376]

Answer:

6 hot dogs, 2 drinks

Step-by-step explanation:

let y = number of hot dogs

let x = number of drinks

system:

y = 3x

4.5y + 2.25x = 31.50   (standard form:  y = -1/2x + 7)

if you graph the system, lines intersect at (2, 6)

6 0
2 years ago
A particle moves along the x-axis with velocity v(t) = t2 - 1, with t measured in seconds and v(t) measured in feet per second.
Kisachek [45]

Answer:

0.667 feet

Step-by-step explanation:

To get the total distance travelled, we would integrate the velocity v(t) equation with respect to time t.

Given that the particle moves from t = 0 to t = 2 seconds

Integrating v(t) = t2 - 1

we get

= t^3/3 - t

substituting the boundaries from t = 0 to t = 2 seconds, we get

= 2^3/3 - 2 - (0^3/3 - 0)

= 8/3 - 2 - 0

= 0.667 feet

8 0
3 years ago
Read 2 more answers
1
nevsk [136]
B. 0

Explanation: at sea level is 0, below sea level would be a negative such as -2, and above sea level is any number above zero, such as 2.
3 0
2 years ago
M angle PQS= 3x; m angle SQR=5x-20 <br> Find x
Dahasolnce [82]

Let as consider the complete ques is : Ray QS bisects ∠PQR. Solve for x and find m∠PQR. m∠PQS = 3x ; m∠SQR = 5x-20.

Given:

Ray QS bisects ∠PQR.

m∠PQS = 3x

m∠SQR = 5x-20

To find:

The value of x and m∠PQR

Solution:

Ray QS bisects ∠PQR. So,

m\angle PQS=m\angle SQR

3x=5x-20

3x-5x=-20

-2x=-20

x=10

The value of x is 10.

Now,

m\angle PQR=m\angle PQS+m\angle SQR

m\angle PQR=3x+5x-20

m\angle PQR=8x-20

Put x=10,

m\angle PQR=8(10)-20

m\angle PQR=80-20

m\angle PQR=60

Therefore, the m∠PQR is 60 degrees.

5 0
3 years ago
"A class of 30 students took midterm science exams. 20 students passed the chemistry exam, 14 students passed physics, and 6 stu
katen-ka-za [31]
The answer is the letter B 
4 0
3 years ago
Read 2 more answers
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