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AlladinOne [14]
3 years ago
9

Question 3

Mathematics
2 answers:
Sav [38]3 years ago
6 0

Answer:

In order for line AE to equal line BF, m/DFB and m/CEA must both be 90°. When this occurs, line AB does not intersect line EF: the two lines are parallel. line AE and line BF represent the perpendicular distances between line AB and line CD. When the two lines are parallel, the perpendicular distance between them is the same throughout their length.

Step-by-step explanation:

sample answer from question.

andriy [413]3 years ago
6 0

Answer:

In order for line AE to equal line BF, m/DFB and m/CEA must both be 90°. When this occurs, line AB does not intersect line EF: the two lines are parallel. line AE and line BF represent the perpendicular distances between line AB and line CD. When the two lines are parallel, the perpendicular distance between them is the same throughout their length.

Step-by-step explanation:

Plato Sample Question

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A regression equation is determined that describes the relationship between average January temperature (degrees Fahrenheit) and
Musya8 [376]

Answer:

Decreases by 2 degrees

Step-by-step explanation:

The expression that describes temperature as a function of latitude is:

T=110-2(Latitude)

This equation represents a linear relationship between latitude and temperature in a way that an increase in latitude causes a decrease in temperature. The magnitude of this decrease is quantified by the slope of the linear equation, which is -2. Therefore, the estimated temperature decreases by 2 degrees when latitude is increased by one.

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3 years ago
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7 0
3 years ago
Write the first six terms of the geometric sequence with the first term 6 and common ratio 1/3
Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn  = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

6 0
2 years ago
Which set of ordered pairs could be generated by an exponential function ?
lawyer [7]

Answer:

The third choice is the correct answer

Step-by-step explanation:

The set of ordered pairs which could be generated by an exponential function is

(1,\frac{1}{2}),(2,\frac{1}{4}),(3,\frac{1}{8}),(4,\frac{1}{16})

If we examine the y-values of this set of ordered pairs, we can see that they have a common ratio of

r=\frac{1}{4}\div \frac{1}{2}

r=\frac{1}{4}\times 2

r=\frac{1}{2}

This makes it exponential.

6 0
3 years ago
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Serga [27]

Answer:

I love a building that's nothing feet high

Step-by-step explanation:

Can that building be my new home?

5 0
3 years ago
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