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3 years ago

Point N is on line segment MO. Given MO = 3x - 10, NO = x, and M N = 8,

Mathematics

1 answer:

alexandr402 [8]3 years ago

3 0

Answer:

MO = 17

Step-by-step explanation:

First, you need to define what if the unknown x.

segment MN and NO are equal to MO.

thus, your equation for the combination is x +8

Now set the values equal to each other

x + 8 = 3x - 10 (subtract x from both sides)

8 = 2x - 10 ( get your x value alone, add 10 to both sides)

18 = 2x (simplfy)

x = 9

Now plug x value into MO

3 (9) - 10 = 17

Check with opposing equation:

9 + 8 = 17 √

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Two skaters are practicing at the same time on the same rink. A coordinate grid is superimposed on the ice. One skater follows t

myrzilka [38]

Answer:

The skaters will collide at the points;

(2,28) and (4,24)

Step-by-step explanation:

The points they might collide will be the points when both y are equal;

-2x + 32 = -2x^2 + 18x

2x^2 -18x -2x + 32 = 0

2x^2 -20x + 32 = 0

2x^2 - 16x - 4x + 32 = 0

2x(x -8) -4( x -8) = 0

(2x -4)(x -8) = 0

2x = 4 or x = 8

x = 4/2 or x = 8

hence; x = 2 or 8

Now let’s get the y value

at x = 2, just substitute into any of the 2

y = -2x + 32

y = -2(2) + 32

y = -4 + 32 = 28

at x = 4

y = -2(4) + 32

y = -8 + 32

y = 24

The points that they will collide are;

(2,28) and (4,24)

4 0

3 years ago

On Monday, three hundred ninety - two students went on a trip to the zoo. All nine buses were filled and five students had to tr

Vikki [24]

The answer to your question is 43

5 0

3 years ago

Please help ASAP brainliest.

lisov135 [29]

Answer:

$\left[\begin{array}{cc}2&8\\5&1\end{array}\right]$

Step-by-step explanation:

The <em>transpose of a matrix </em> $M^T$ is one where you swap the column and row index for every entry of some original matrix $M$ . Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation $p_{i,j}$ and $p^T_{i,j}$ to refer to the entry in the i-th row and the j-th column of the matrices $P$ and $P^T$ respectively:

$p_{1,1}=p^T_{1,1}=2\\p_{1,2}=p^T_{2,1}=5\\p_{2,1}=p^T_{1,2}=8\\p_{2,2}=p^T_{2,2}=1\\$

Constructing the matrix $P^T$ from those entries gives us

$P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]$

which is option a. from the list.

Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!

7 0

3 years ago

Dividing, -please please please help?

harkovskaia [24]

B should be the answer Hope this helps.

5 0

3 years ago

A lent B rs 32500 to purchase a car at 12.5% p.A

LiRa [457]

Answer:

6,483.75

Step-by-step explanation:

Calculation to find the interest paid by B after 3/2 year

First step is to calculate the Compound interest amountUsing this formula

Interest paid= P(1 + r/100)^Time

Where,

P represent principal=32,500

r represent Rate of interest = 12.5%/2 = 6.25%

T represent Time=3/2 years

Let plug in the formula

Compound interest amount= 32,500(1 + 6.25/100)^2*3/2

Compound interest amount= 32,500([1+.0625)^3

Compound interest amount= 32,500(1.0625)^3

Compound interest amount= 32,500 *1.1995

Compound interest amount= 38,983.75

Now let calculate the Interest paid by B

Interest paid by B = 38,983.75 - 32,500

Interest paid by B = 6,483.75

Therefore the interest paid by B after 3/2 year will be 6,483.75

7 0

3 years ago