All categories

3 years ago

Compare 7/8 with 14/16 using ( <, >, =).

Mathematics

2 answers:

Sindrei [870]3 years ago

6 0

Answer:
A

Solving steps:
divide 14/16 by 2 and you’ll get 7/8 hope i helped :)

MA_775_DIABLO [31]3 years ago

3 0

Answer:

Step-by-step explanation:

multiply 7/8 by 2/2 to get 14/16. they are equal

You might be interested in

Write an equation in standard form for the line, where the points (-2, -1) and (0, 4) are on the line

DedPeter [7]

Answer:

An equation in standard form for the line is:

$\frac{5}{2}x-y=-4$

Step-by-step explanation:

Given the points

(-2, -1) and (0, 4)

The slope between two points

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(0,\:4\right)$

$m=\frac{4-\left(-1\right)}{0-\left(-2\right)}$

$m=\frac{5}{2}$

Writing the equation in point-slope form

As the point-slope form of the line equation is defined by

$y-y_1=m\left(x-x_1\right)$

Putting the point (-2, -1) and the slope m=1 in the line equation

$y-\left(-1\right)=\frac{5}{2}\left(x-\left(-2\right)\right)$

$y+1=\frac{5}{2}\left(x+2\right)$

$y=\frac{5}{2}x+4$

Writing the equation in the standard form form

As we know that the equation in the standard form is

$Ax+By=C$

where x and y are variables and A, B and C are constants

$y=\frac{5}{2}x+4$

$\frac{5}{2}x-y=-4$

Therefore, an equation in standard form for the line is:

$\frac{5}{2}x-y=-4$

7 0

3 years ago

The price of a pair of shoes increases from $64 to $66. What is the percent increase to the nearest percent? The percent increas

Strike441 [17]

Answer:

Percent symbol 2 I think

5 0

3 years ago

Read 2 more answers

7. A line of symmetry divides a design so that every point on one side of the line

SVEN [57.7K]

Answer:

ok here is the answer 3 3/6

Step-by-step explanation:

4 0

3 years ago

U may not understand this but what is 10 g/cm³ a measure of . is it Volume Mass or density

prisoha [69]

Density. Unit of Mass is Kg or gram or pound. Unit of Volume is cubic meter/cm or whatever the length unit used.

6 0

3 years ago

Find the distance of the point (4,4,−4) from the line r(t)=⟨−1+2t,1+2t,3−3t⟩.

Nadusha1986 [10]

Translate the given point and line together so that you get a new point and a new line that passes through the origin. This turns the problem into finding the distance between the new point,

p = (4, 4, -4) - (-1, 1, 3) = (5, 3, -7)

and the new line,

r*(t) = r(t) - ⟨-1, 1, 3⟩ = ⟨2t, 2t, -3t⟩

Let p = ⟨5, 3, -7⟩, the vector starting at the origin and pointing to p. Then the quantity ||p - r*(t)|| is the distance from the point p to the line r*(t).

Let u be such that ||p - r*(t)|| is minimized. At the value t = u, the vector p - r*(t) is orthogonal to the line r*(t), so that

(p - r*(u) ) • r*(u) = 0

I've attached a sketch with all these elements in case this description is confusing. (The red dashed line is meant to be perpendicular to r*(t).)

Solve this equation for u :

p • r*(u) - r*(u) • r*(u) = 0

p • r*(u) = r*(u) • r*(u)

and x • x = ||x||² for any vector x, so

p • r*(u) = ||r*(u)||²

⟨5, 3, -7⟩ • ⟨2u, 2u, -3u⟩ = (2u)² + (2u)² + (-3u)²

10u + 6u + 21u = 4u ² + 4u ² + 9u ²

17u ² - 37u = 0

u (17u - 37) = 0

==> u = 0 or u = 37/17

We ignore u = 0, since the dot product of any vector with the zero vector is 0.

Then the minimum distance distance between the given point and line is

||p - r*(u)|| = ||⟨5, 3, -7⟩ - 37/17 ⟨2, 2, -3⟩|| = √(42/17)

6 0

3 years ago