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horrorfan [7]
3 years ago
5

The price of a pair of shoes increases from $64 to $66. What is the percent increase to the nearest percent? The percent increas

e is %.
Mathematics
2 answers:
Strike441 [17]3 years ago
5 0

Answer:

Percent symbol 2 I think

MissTica3 years ago
5 0

Answer:

0.03

Step-by-step explanation:

Percent increase= amount of increase/ original amount  

66 - 64 / 66 = 2 / 66 = 0.0303030303

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antiseptic1488 [7]

Answer:

p(x) = 0.85x

t(x) = 1.065x

(t o p)(x) = 0.9x

$2700

Step-by-step explanation:

If the marked price is $x, then the function p(x) that gives the price of the riding lawn mower after 15% discount will be

p(x) = x(1 - \frac{15}{100}) = 0.85x

where x is the marked price.

Now, the function that gives the total cost with sales tax will be given by

t(x) = x(1 + \frac{6.5}{100}) = 1.065x

where x is the discounted price.

Therefore, the composite function that gives the total cost of the riding lawn mower on sale is given by

(t o p)(x) = 1.065(0.85x) = 0.9x ............ (1)

where x is the marked price.

If the marked price x = $3000, then Mr. Rivera has to pay for the riding lawn mower, from equation (1),

(t o p)(3000) = 0.9 × 3000 = 2700 dollars. (Answer)

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4 years ago
A researcher selects all of the possible samples with n = 8 scores from a population and computes the mean, dividing by n, for e
Nadusha1986 [10]

Answer:

By the Central Limit Theorem, the average value for all of the sample means is 14.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

If the population mean is μ = 14, then what is the average value for all of the sample means?

By the Central Limit Theorem, the average value for all of the sample means is 14.

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Step-by-step explanation:

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He weighed 182 pounds at that point.
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