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3 years ago

Using the following sample space:

Mathematics

2 answers:

san4es73 [151]3 years ago

3 0

Find P (A B) using the additive rule, hope this helps

Agata [3.3K]3 years ago

3 0

Answer:

find p using the additive rule

Step-by-step explanation:

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Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x)<br><br> What is the answer?

notsponge [240]

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

Sorry if its wrong :(

6 0

2 years ago

Identify the vertex<br><br> y= —(x — 6)^2 + 2

alisha [4.7K]

(6,2)

Mark brainliest please

Hope this helps you

8 0

2 years ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0

2 years ago

PLEASE ANSWER ASAP!!!! (and actually answer the question, no begging for "brainliest")

Zepler [3.9K]

Answer:

A: P = 41100 - 590t

B: 34610

Step-by-step explanation:

equation = 41100-(41100-36380)/(2011-2003)t

plug it in

41100 - 590(2014-2003)=34610

4 0

1 year ago

Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?

steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices $P(-2, 6), \ Q(-8, 4), and\ R(1, -2).$ It is translated according to the rule $(x, y)\ -> \ (x\ - \ 2, y\ - 16)$ . What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is $(x, y)\ -> (x - 2, \ y -16).$

Now calculated the vertices P value according to the rule of translated

$P(-2, 6)\\Now \ apply \ the\ translated\ rule \ in\ P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)$

So -10 is the value of y in P vertices .

6 0

3 years ago

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