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3 years ago

Write the equation of a line parallel to y=2x+2 that passes through the point (-1, -7)

Mathematics

1 answer:

alexira [117]3 years ago

7 0

Answer: y=2x-5

Step-by-step explanation:

To find the line that is parallel to y=2x+2, we know the slope must be 2. Parallel lines NEVER touch. That tells us that the slope must be 2. Now, all we have to do is to plug in the point to find the y-intercept.

-7=2(-1)+b [multiply]

-7=-2+b [add both sides by 2]

b=-5

With the y-intercept, we can find the parallel line.

y=2x-5

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(b) How much the selling price should be fixed for pulse bought for Rs.70 per kg. to earn a profit of Rs.6 after allowing a 5 %

Mama L [17]

Answer:

Rs. 80

Step-by-step explanation:

Given that :

Purchase price = 70

Profit = 6

Discount = 5%

Let selling price = x

Selling price * (1 - discount) = (purchase price + profit)

x * (1 - 5%) = (70 + 6)

x * (1 - 0.05) = 76

x * 0.95 = 76

0.95x = 76

x = 76 / 0.95

x = 80

Hence, selling price = Rs. 80

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3 years ago

Write the exponential equation in logarithmic form. e^(-3) ≈ .05

vodka [1.7K]

Answer:

-3 = ln(0.05)

Step-by-step explanation:

Taking the natural log of both sides of the equation gives ...

-3·ln(e) = ln(0.05)

The natural log of e is 1, so the equation becomes ...

-3 = ln(0.05)

7 0

3 years ago

A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.

Papessa [141]

Answer:

$\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}$

Step-by-step explanation:

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

$\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}$

$\bf \implies n_{cubes} = \dfrac{20cm \times 6cm \times 4cm .}{2cm \times 2cm \times 2cm } \\\\\bf\implies n_{cubes} = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }$

<h3>Hence the number of cubes that can be fitted in the box is 60 .</h3>

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3 years ago

-2r+11=13 2r=2 r= I need help

Artemon [7]

Answer:

-2r = 2 - Subtract 11 from both sides

r = -1

5 0

2 years ago

At which root does the graph of f(x) = (x + 4) 6(x + 7)5 cross the x-axis? 0 -7 ООО

Maslowich

the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x = -7$ .

Step-by-step explanation:

We have , f(x) = (x + 4) 6(x + 7)5 i.e. $f(x) = (x+4)^{6}(x+7)^{5}$ . We need to find root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0. Let's solve this:

⇒ $f(x) = (x+4)^{6}(x+7)^{5}$

⇒ $0 = (x+4)^{6}(x+7)^{5}$

⇒ $(x+4)^{6}(x+7)^{5} = 0$

Which means either $x+4 = 0\\x = -4$ or , $x+7=0\\x=-7$ . That means the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x= -4$ or $x = -7$ . ∴ From given options , the root for which the graph of $f(x) = (x+4)^{6}(x+7)^{5}$ cross the x-axis i.e. value of y or f(x) = 0 is $x = -7$ .

3 0

4 years ago

Write the equation of a line parallel to y=2x+￼2 that passes through the point (-1, -7)￼

Write the equation of a line parallel to y=2x+2 that passes through the point (-1, -7)