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weqwewe [10]
3 years ago
7

Write the equation of a line parallel to y=2x+2 that passes through the point (-1, -7)

Mathematics
1 answer:
alexira [117]3 years ago
7 0

Answer: y=2x-5

Step-by-step explanation:

To find the line that is parallel to y=2x+2, we know the slope must be 2. Parallel lines NEVER touch. That tells us that the slope must be 2. Now, all we have to do is to plug in the point to find the y-intercept.

-7=2(-1)+b            [multiply]

-7=-2+b                [add both sides by 2]

b=-5

With the y-intercept, we can find the parallel line.

y=2x-5

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[(y+4)/(y+7)]+1=(y+3)/(y+1)
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<span>First note that y cannot equal -7 or -1 as division by zero is undefined.  So that if it comes up in our solution we know that it is not a real solution.

[(y+4)/(y+7)]+1=(y+3)/(y+1)  make the left side have a common denominator

(y+4+y+7)/(y+7)=(y+3)/(y+1)  combine like terms on left side

(2y+11)/(y+7)=(y+3)/(y+1)  cross multiply 

(2y+11)(y+1)=(y+3)(y+7)  expand

2y^2+13y+11=y^2+10y+21  subtract y^2 from both sides

y^2+13y+11=10y+21  subtract 10y from both sides

y^2+3y+11=21 subtract 21 from both sides

y^2+3y-10=0  expand so factoring is easier

y^2-2y+5y-10=0  factor

y(y-2)+5(y-2)=0  which is equal to

(y+5)(y-2)=0

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6 0
3 years ago
What is the slope of the line shown?<br> (0.4)<br> (54)
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Answer:

The slope of any horizontal line is 0!

Step-by-step explanation:

6 0
3 years ago
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eight cards are drawn from a standard deck of 52 cards. how many hands off with cards contain exactly three queens and three jac
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Answer:

15,136 hands off with cards contain exactly three queens and three jacks.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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4 queens and 4 jacks.

The other 52 - 8 = 44 cards are neither queens nor jacks.

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3 queens from a set of 4.

3 jacks from a set of 4.

2 other cards(not queens neither jacks) from the other 44. So

C_{4,3}C_{4,3}C_{44,2} = \frac{4!}{1!3!} \times \frac{4!}{1!3!} \frac{44!}{2!42!} = 4*4*22*43 = 15136

15,136 hands off with cards contain exactly three queens and three jacks.

4 0
3 years ago
Sanjay and Felipe are putting together a 500-piece puzzle. Sanjay could do the entire puzzle by himself in 6 hours, while it wou
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Let's assume initial population is in 1999

so, production of passenger cars in Japan is 3.94 million in 1999

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now, we can solve for

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so,

the geometric mean annual percent increase is 5.516%............Answer

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