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Scrat [10]
3 years ago
12

The vertex of a quadratic equation is given at (−2, 1), and the quadratic is concave up. How can the range and domain be describ

ed?
Question options:

Domain: [1, ∞)
Range: (−∞, ∞)

Domain: (−∞, ∞)
Range: [1, ∞)

Domain: [−2, ∞)
Range: (−∞, ∞)

Domain: (−∞, ∞)
Range: [−2, ∞)
Mathematics
1 answer:
Leto [7]3 years ago
3 0
Answer:
First answer
Explanation:
Just as a reminder, domain is the x values that would give a defined answer for y, and range is the possible values y could get.
The domain of every polynomial is (-infinity, infinity), because there isn’t any value that could make it undefined.
Since this is an upward opening parabola, it’s vertex is its minimum point, which is 1. That means the range would be [1, infinity).
This means the answer is:
Domain: [1, infinity)
Range: ( -infinity, infinity)
I hope this helped.
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Increasing: x and x>1.

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Step-by-step explanation:

We have been given a function f(x)=x^3-3x+4. We are asked to determine the intervals, where the function is increasing and where it is decreasing.

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Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

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f'(0)=3(0)^{2}-3=0-3=-3

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We will check 2 from our 3rd interval.

f'(2)=3(2)^{2}-3=3(4)-3=12-3=9

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Start out small.
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