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zaharov [31]
2 years ago
6

Help guysss find the slope of the line

Mathematics
2 answers:
aliina [53]2 years ago
6 0

Answer:

Step-by-step explanation:

3. (1, 2)  (2, 4)

 (4 - 2)/(2 - 1)= 2/1 = 2

4. (5, 2) (10, 4)

    (4 - 2)/(10 - 5) = 2/5

5. (4, 1) (8, 2)

   (2 - 1)/(8 - 4) = 1/4

6. (0, 0)  (1, 20)

   (20 - 1)/(1 - 0)

   20/1= 20

Elis [28]2 years ago
5 0
What is the equation?
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A water tank in Stewart's
lara [203]

The change in the volume of water in 1 minute is a decrease of 0.16 milliliters.

Since a water tank in Stewart's home had a small, steady leak loss of 1 3/5 mL in 10 min, to find the change in the volume of water in 1 minute, the following calculation must be performed:

  • The total leak must be calculated and divided by the 10 minutes duration.  
  • 3/5 = 0.6
  • 1 + 0.6 = 1.6
  • 1.6 / 10 = 0.16

Therefore, the change in the volume of water in 1 minute is a decrease of 0.16 milliliters.

Learn more in brainly.com/question/19747831

3 0
2 years ago
Alicia borrowed $15,000 to buy a car. She borrowed the money at 8% for 6 years. What is the interest rate she will pay for the l
Likurg_2 [28]
First convert the rate into a decimal.
8/100=0.08
Next put all those numbers 15,000, 0.08, and 6 into the equation A=P(1+(rt)).
This is how you do it.
A=15,000(1+(0.08*6))
A=15,000(1+0.48)
A=15,000(1.48)
A=22,200
7 0
3 years ago
HELP ASAP 5 POINTS...................
11111nata11111 [884]
The answer is A. one of the zeros is x = -1
3 0
2 years ago
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devlian [24]
If arc =AB is equal to arcCD then line AB should equa lineCD
8 0
3 years ago
Simplify: x0 y-3 / x2 y-1
svetlana [45]

\frac{x {}^{0}y {}^{ - 3}  }{x {}^{2}y {}^{ - 1}  }  \\  =  \frac{1y {}^{ - 3} }{ {x}^{2}y {}^{ - 1}  }  \\  =  \frac{1 \times 1}{ {x}^{2} y {}^{2} }  \\    \\  =  \frac{1}{ {x}^{2}y {}^{2}  }

Step by Step Explanation:

  • Evaluate the power: Any non-zero expression raised to the power of 0 equals 1
  • Simplify: Simplify the expression
  • Calculate the product: Any expression multiplied by 1 remains the same.

<h2>☆彡Hanna</h2>

#CarryOnLearning

8 0
2 years ago
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