Answer:
3.5
Step-by-step explanation:
21 (pages) divided by 6 (minutes) = 3.5 per minute
Answer:
3
Step-by-step explanation:
The athlete that has the shortest training ride is athlete A.
The athlete that has the shorter range is Athlete B.
The athlete that has the greater median is Athlete B.
The athlete that has the greater IQR is athlete A.
<h3>What are the summary statistics?</h3>
A box plot is used to study the distribution and level of a set of scores. The box plot consists of two lines and a box. the two lines are known as whiskers. The first whisker represents the minimum number and the second whisker represents the maximum number. The difference between the whiskers is known as range.
Range of Athlete A = 36 - 13 = 13
Range of Athlete B = 30 - 19 = 11
Training ride of Athlete A = 16
Training ride of Athlete B = 21
On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile.
Median of Athlete A = 20
Median of Athlete B = 25
IQR of Athlete A = 30 - 16 = 14
IQR of Athlete B = 28 - 21 = 7
To learn more about box plots, please check: brainly.com/question/27215146
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Answer:
$23.32
Step-by-step explanation:
Add $22 and $1.32 to get the total.
$22 + $1.32 = $23.32
We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.
F '(x) = -4x^3 - 27x^2 - 48x - 16 You must set this = to 0 and solve for the
roots (which we call "critical values).
F "(x) = -12x^2 - 54x - 48
Now suppose you've found the 3 critical values. We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).
Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:
F "(x) = -12x^2 - 54x - 48 becomes F "(4) = -12(4)^2 - 54(4)
= -192 - 216
Because F "(4) is negative, the graph of the given
function opens down at x=4, and so we have a
relative max there. (Remember that "4" is only
an example, and that you must find all three
critical values and then test each one in F "(x).
