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Ganezh [65]
3 years ago
15

A bag contains 2 yellow marbles and 5 red marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a

second marble is drawn. What is the probability that the first marble is red and the second one is yellow?
Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

Number of red balls = 5  Number of orange balls = 2

Number of yellow balls = 1

Number of green balls = 2

Therefore total number of balls = 10.

Probability of getting a ball =   P(choosing orange ball) =  After picking an orange ball, we are left with 9 ballsP ( choosing a green ball) = P(choosing an orange marble and a green marble) = 0.04444 is the approximate probability of choosing an orange marble and a green marble.

Step-by-step explanation:

You might be interested in
What’s 9n-3 simplified
Katarina [22]

Answer:

9n-3

Step-by-step explanation:

since 9n has a variable, u can't add or subtract 9n with 3

but if you were multiplying: 9n(3) then it would be 27n

:)

7 0
2 years ago
The price of grapes at the grocery store is $1.44 per pound. There are approximately 0.45 kilometers in a pound. To the nearest
Nadusha1986 [10]
0.45 * 2 is 0.9
$1.44 * 2 is $2.88
$1.44/9 is $0.16
$0.16 * 2 is $0.32
$2.88+$0.32 is $3.20

The answer is $3.20
5 0
3 years ago
A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec
VMariaS [17]

Answer:

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=19.1 represent the sample mean

\mu population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that t_{\alpha/2}=

Now we have everything in order to replace into formula (1):

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

5 0
3 years ago
Which of the following inequalities is not true?
Lemur [1.5K]

Answer:

| - 9|  =  |9|

This is because modulus number will be always positive

Hope this is correct and helpful

HAVE A GOOD DAY!

4 0
3 years ago
If there are 15 students who don’t wear glasses, how many students are in the class?
mixer [17]
Ummmm still 15???????
4 0
2 years ago
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