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soldi70 [24.7K]
3 years ago
9

A company has introduced two new products to the market. The revenue generated by product A was $63,000 in the first year, and t

he revenue increases by 3.5% every year.
The revenue generated by product B was $81,000 in the first year, and the revenue increases by 2.1% every year.

Which function can the company use to determine its total revenue from the two products, R(x), after they have been on the market for x years, and approximately what will be the revenue generated by sales of the products after 6 years?

R(x) = 9,000[7(1.035)x + 9(1.021)x]; $635,580
R(x) = 9,000[7(1.035)x + 9(1.021)x]; $169,200
R(x) = 9,000[9(1.035)x + 7(1.021)x]; $170,936
R(x) = 9,000[9(1.035)x + 7(1.021)x]; $688,050
Mathematics
2 answers:
elena-s [515]3 years ago
6 0
The correct answer is <span>R(x) = 9,000[9(1.035)x + 7(1.021)x]; $170,936</span>
meriva3 years ago
6 0
For this case we have functions of the form:
 y = A (b) ^ x
 Where,
 A: initial amount
 b: growth rate
 x: time
 Therefore, substituting values we have:
 Product A:
 y = 63000 (1,035) ^ x
 Product B:
 y = 81000 (1,021) ^ x
 The sum of the products is:
 R (x) = 63000 (1,035) ^ x + 81000 (1,021) ^ x
 Rewriting:
 R (x) = 9000 (7 (1,035) ^ x + 9 (1,021) ^ x)
 Evaluating for 6 years:
 R (6) = 9000 * (7 * (1,035) ^ 6 + 9 * (1,021) ^ 6)
 R (6) = 169200 $
 Answer:
 
The revenue generated by sales of the products after 6 years is:
 
R (x) = 9,000 [7 (1,035) x + 9 (1,021) x]; $ 169,200
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Using Pythagoras theorem

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The $1 coin here depicts Sacagawea and her infant son. The diameter of the coin is 26.5 millimeters. Find the circumference. Use
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83.21 mm.<span>

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6 0
1 year ago
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least... 

<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>

<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>

<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>

<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>

<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>

<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>

<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>

<span>Now apply the Law of Sines to find the other two angles. </span>

<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>

<span>Two down, one to go... </span>

<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>

<span>So your three angles are: </span>

<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
8 0
3 years ago
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