Answer:
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Step-by-step explanation:
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
The car is faster because it’s 120km/hr, wile the train is 75km/hr
4x-10 and 7x-8 are supplementary angles and thus add up to 180 degrees.
Thus, 11x - 18 = 180 degrees.
Combining like terms, 11x = 198, and x = 18.
The two supplementary angles are 4(18)-10 and 7(18)-8, or 62 and 118 degrees.
