All categories

3 years ago

Whats closest to 5/6? 0,1/2? Or 1 Please explain why :) thanks

Mathematics

2 answers:

sp2606 [1]3 years ago

8 0

The closest number to 5/6 would have to be 1

1) 0 wouldn't be the answer because the fraction would have to look like 0/6, 1/6, or 2/6

2) 1/2 wouldn't be the answer because half of 6 is 3 ---> 3/6

3) 1 would be the answer because 5/6 is close to 6/6, which is one whole.

Vladimir79 [104]3 years ago

4 0

1, because 0, is 0/6, 1/2 also equals 3/6, and 1 equals 6/6. Of all these numbers, 5/6 is closest to 6/6 which equals one.
If this is confusing for you, take out the denominators: think logically. Is 5 closer to 0, 3, or 6?
6.
Therefore, when you plug back in the denominators, the answer is 6/6 or 1.

You might be interested in

Which number in the monomial 125x^18 y^3 z^25 need to be changed to make it a perfect cube

Serhud [2]

The power of 25 on the variable z needs to be changed. It has to be divisible by 3.

6 0

3 years ago

Someone plz help on # 15 (idk what to do) :/

aleksklad [387]

Answer:

2x-5= -20

move -5 to the other side

sign changes from -5 to 5

2x-5+5= -20+5

2x= -15

divide by 2 for both sides

2x/2= -15/2

cross out 2 and 2, divide by 2 and 2 and then becomes x

x= -15/2

4 0

3 years ago

(-4,5) and (4,0) find the distance between each pair of points

aleksklad [387]

Answer:

9.4339 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where

$(x_1,y_1) = (-4,5)$

$(x_2,y_2) = (4,0)$

Replacing these values in the distance formula

$D =\sqrt{(-4-4))^2+(5-0)^2}$

$D =\sqrt{(-8)^2+(5)^2}$

$D =\sqrt{64+25}$

$D =\sqrt{89}$

$D= 9.4339$

Hence the distance is 9.4339 units

6 0

3 years ago

Number of edges of hexahedron

vlabodo [156]

Answer:

6 edges

I hope it helps

8 0

1 year ago

Read 2 more answers

Please help will mark brainliest

beks73 [17]

Answer:

$m\angle N=57^{\circ}$

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares $LM\cong LN$ , the remaining unknown angles are equal ( $m\angle N=m\angle M$ ). The sum of the interior angles of a triangle always add up to $180^{\circ}$$ .

Therefore:

$m\angle N\cdot 2+66=180,\\m\angle N\cdot 2=114,\\m\angle N=\fbox{$57^{\circ}$}$ .

7 0

3 years ago

Read 2 more answers