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3 years ago

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Brett and Irving need 2 1/2 meters of fabric to make a large pillowcase. Brett has 1 3/4 meters of fabric. Irving has 3/2 meter

of fabric. Do Brett and Irving have enough fabric?

2 answers:

Mama L [17]3 years ago

5 0

Answer:

yessir

Step-by-step explanation:

yesyesyesyesyesyesyesyesyessssssss

♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥

Colt1911 [192]3 years ago

3 0

Answer: Yes

Step-by-step explanation:

Hi, to answer this question we have to add Brett's and Irwin's meters of fabric and compare:

1 3/4 + 3/2 = (4(1)+3)/4 + 3/2 = 7/4 + 3/2 = 7/4 + 3(2)/2(2) = 7/4 +6/4 =13/4 m

Total meters of fabric available = 23/6m = 3.25m (in decimal form)

Meters of fabric needed = 2 1/2 = 5/2 = 2.5 m

Since the meters available are greater than the meters needed:

3.25> 2.5

They have enough fabric.

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In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

Marina86 [1]

Answer:

(a) 0.94

(b) 0.20

(c) 90.53%

Step-by-step explanation:

From a population (Bernoulli population), 90% of the bearings meet a thickness specification, let $p_1$ be the probability that a bearing meets the specification.

So, $p_1=0.9$

Sample size, $n_1=500$ , is large.

Let X represent the number of acceptable bearing.

Convert this to a normal distribution,

Mean: $\mu_1=n_1p_1=500\times0.9=450$

Variance: $\sigma_1^2=n_1p_1(1-p_1)=500\times0.9\times0.1=45$

$\Rightarrow \sigma_1 =\sqrt{45}=6.71$

(a) A shipment is acceptable if at least 440 of the 500 bearings meet the specification.

So, $X\geq 440.$

Here, 440 is included, so, by using the continuity correction, take x=439.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{339.5-450}{6.71}=-1.56$ .

So, the probability that a given shipment is acceptable is

$P(z\geq-1.56)=\int_{-1.56}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}}=0.94062$

Hence, the probability that a given shipment is acceptable is 0.94.

(b) We have the probability of acceptability of one shipment 0.94, which is same for each shipment, so here the number of shipments is a Binomial population.

Denote the probability od acceptance of a shipment by $p_2$ .

$p_2=0.94$

The total number of shipment, i.e sample size, $n_2= 300$

Here, the sample size is sufficiently large to approximate it as a normal distribution, for which mean, $\mu_2$ , and variance, $\sigma_2^2$ .

Mean: $\mu_2=n_2p_2=300\times0.94=282$

Variance: $\sigma_2^2=n_2p_2(1-p_2)=300\times0.94(1-0.94)=16.92$

$\Rightarrow \sigma_2=\sqrt(16.92}=4.11$ .

In this case, X>285, so, by using the continuity correction, take x=285.5 to compute z score for the normal distribution.

$z=\frac{x-\mu}{\sigma}=\frac{285.5-282}{4.11}=0.85$ .

So, the probability that a given shipment is acceptable is

$P(z\geq0.85)=\int_{0.85}^{\infty}\frac{1}{\sqrt{2\pi}}e^{\frac{-z^2}{2}=0.1977$

Hence, the probability that a given shipment is acceptable is 0.20.

(c) For the acceptance of 99% shipment of in the total shipment of 300 (sample size).

The area right to the z-score=0.99

and the area left to the z-score is 1-0.99=0.001.

For this value, the value of z-score is -3.09 (from the z-score table)

Let, $\alpha$ be the required probability of acceptance of one shipment.

So,

$-3.09=\frac{285.5-300\alpha}{\sqrt{300 \alpha(1-\alpha)}}$

On solving

$\alpha= 0.977896$

Again, the probability of acceptance of one shipment, $\alpha$ , depends on the probability of meeting the thickness specification of one bearing.

For this case,

The area right to the z-score=0.97790

and the area left to the z-score is 1-0.97790=0.0221.

The value of z-score is -2.01 (from the z-score table)

Let $p$ be the probability that one bearing meets the specification. So

$-2.01=\frac{439.5-500 p}{\sqrt{500 p(1-p)}}$

On solving

$p=0.9053$

Hence, 90.53% of the bearings meet a thickness specification so that 99% of the shipments are acceptable.

8 0

3 years ago

Helpppp me please!!!!

harina [27]

Hey there, again! :D

Since the angle measuring 38 degrees is adjacent to m<1, it will equal 180 degrees.

180-38= 142

m<1= 142 degrees

I hope this helps!
~kaikers

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3 years ago

14) What is the distance between −2 + 1 and 4 + 5 a) √10 b

Svetllana [295]

Answer:

$\sqrt52$

Step-by-step explanation:

(-2,1)=(x1,y1)

(4,5)=(x2,y2)

d=?

d= $\sqrt(4+2)2 + (5-1)2\\\sqrt(6)2+(4)2\\\sqrt36+16\\\sqrt52\\$

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3 years ago

Which option shows the graph of 3y+18>5x

andrew-mc [135]

Hi, I'm so sorry I can't answer that. but I have something you can answer that. Search in browser or anything searcher that you have "Quickmath" or "Cymath" all your equations,problems can solved

Step-by-step explanation:

i hope it helps

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3 years ago

How many times does 8 go into 66

Romashka [77]

8 will go into 66 , 8.25 times

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