8 2/3
because 6 1/2 divided by 3/4 is 8 2/3
Wouldn't it be zero? because only 0 is less than 2 in this case
Answer:
a
Step-by-step explanation:
Given
![y=x^2-6x+8](https://tex.z-dn.net/?f=y%3Dx%5E2-6x%2B8)
To obtain the minimum value of y, we first take the derivative of y
The derivative of y is:
![y^{\prime}=2x-6](https://tex.z-dn.net/?f=y%5E%7B%5Cprime%7D%3D2x-6)
Equating
![y^{\prime}\text{ = 0}](https://tex.z-dn.net/?f=y%5E%7B%5Cprime%7D%5Ctext%7B%20%3D%200%7D)
gives the minimum value we require.
Doing that, we have:
![2x-6=0](https://tex.z-dn.net/?f=2x-6%3D0)
So that
![\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%202x%3D6%20%5C%5C%20x%3D%5Cfrac%7B6%7D%7B2%7D%20%5C%5C%20%3D3%20%5Cend%7Bgathered%7D)
Therefore, the minimum value is x = 3
Answer:
54
Step-by-step explanation: