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3 years ago

What is the coeffiect of 5/3 xy

1 answer:

8 0

The coefficient is the constant part of a monomial, basically the number in front of the variable, in this expression it is 5/3

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Help, I have a time limit for this

salantis [7]

Answer:

I believe that it is the first one.

Step-by-step explanation:

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3 years ago

6) What is the mystery number?

valkas [14]

9.333048
is what I believe the mystery number would be

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3 years ago

Read 2 more answers

A number multiplied by -8, subtracted from the sum of 14 and five times the number

Charra [1.4K]

Let us suppose the number is x. Now we try to make an algebraic expression going step by step.

Step 1:

Five times the number means 5 multiplied by x.

So it becomes 5x.

Step 2:

Sum of 14 and five times the number means 5x+14.

Step 3:

Number multiplied by -8 means -8x.

Step 4:

Subtract the expression in step (3) from expression in step (2)

5x+14-(-8x)

Now we can simplify it further,

5x+14+8x

Combining like terms,

13x+14

Answer: The final expression becomes 13x+14.

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3 years ago

Read 2 more answers

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

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3 years ago

Henry spent 7 6/9 hours working on his reading and math homework.If he spent 6 7/8 on his reading homework,how much time did he

jeyben [28]

GCM of 8 and 9 is 72

6/9 = 64/72
7/8 = 63/72

1 1/72

6 0

3 years ago