What is the coeffiect of 5/3 xy
1 answer:
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Answer:
<em>a. The system of equations that models the situation is....</em>
<em> </em>
<em>b. The solution to the system: x = 2 and y = 4 </em>
<em>The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.</em>
Step-by-step explanation:
Suppose, the amount of 80/20 mixture is pounds and the amount of 50/50 mixture is
pounds.
So, the amount of peanuts in 80/20 mixture pound and the amount of almonds in 80/20 mixture
pound.
And the amount of peanuts in 50/50 mixture pound and the amount of almonds in 50/50 mixture
pound.
Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.
So, the amount of peanuts in that mixture pounds
and the amount of almonds in that mixture pounds.
So, the system of equations will be.........
Subtracting equation (2) from equation (1), we will get.....
Now, plugging this into equation (1), we will get......
So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.
It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: 
. FOIL out the left side to get 
. FOIL out the first of the 2 expressions on the right to get 
, and the second of the 2 to get 4x. Our equation now looks like this: 
. Combine like terms to get an equation that still has square roots in it that we have to deal with: 
and 
. We will square both sides to get rid of the square root sign. 
. This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. 
. Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2