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2 years ago

Who knows what 0.976 + 0.99

Mathematics

2 answers:

koban [17]2 years ago

5 0

I believe the answer is 1.966

jeka57 [31]2 years ago

3 0

The answer is 1.966
I hope i helped:)

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A farmer bought a number of pigs for $160. However, 8 of them died before he could sell the rest at a profit of 6 per pig. His t

juin [17]

Answer:

The farmer bought 36 pigs in all.

Step-by-step explanation:

Given that a farmer bought a number of pigs for $ 160, but, however, 8 of them died before he could sell the rest at a profit of 6 per pig, and his total profit was $ 8, to determine how many pigs did he originally buy the following calculation must be performed:

160 + 8 = 168

168/6 = 28

28 + 8 = 36

Thus, the farmer bought 36 pigs in all.

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2 years ago

Pls help, algebra 1<br>

AURORKA [14]

Answer:

20, 35, 50

Step-by-step explanation:

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2 years ago

An oil company fills 1/12 of a tank in 1/3 hour. At this rate, which expression can be used to determine how long will it take f

monitta

Selection B is appropriate.

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It takes 12 times as long to fill the whole tank as it does to fill 1/12 of the tank.
.. 12 * (1/3 hour) = (1/3)*12 hour

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3 years ago

Read 2 more answers

nine days ago the area covered by a mold on a piece of bread was 3 square inches today the mold covers 9,square inches find the

Gennadij [26K]

The rate of change would be 0.6 to 6

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3 years ago

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(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim

aleksklad [387]

(i) Given that

$V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr$

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

$V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}$

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

$\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

Compute the integral:

$V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

$V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr$

$V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R$

$V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)$

$V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}$

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0

2 years ago