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Contact [7]
3 years ago
10

Complete the point-slope equation of the line through (2,3 and (7,4). Use exact numbers.

Mathematics
1 answer:
uysha [10]3 years ago
3 0

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Step-by-step explanation:

The form of the point-slope equation is y-y_{1}=m(x-x_{1}) , where

  • m is the lope of the line
  • (x_{1},y_{1}) is a point lies on the line

The slope of a line m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where

(x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line

∵ The line through (2 , 3) and (7 , 4)

∴ x_{1} = 2 and x_{2} = 7

∴ y_{1} = 3 and y_{2} = 4

- Substitute these value in the rule of the slope

∵ m=\frac{4-3}{7-2}=\frac{1}{5}

∴ the slope of the line is m=\frac{1}{5}

Let us substitute the value of the slope and the coordinates of point (x_{1},y_{1}) in the form of the equation

∵ y-y_{1}=m(x-x_{1})

∵ x_{1} = 2 and y_{1} = 3

∵ m=\frac{1}{5}

∴ y-3=\frac{1}{5}(x-2)

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Learn more:

You can learn more about the linear equation in brainly.com/question/12941985

#LearnwithBrainly

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Answer:

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Step-by-step explanation:

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Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

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