y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:either c or b
Step-by-step explanation: to be honest I searched up
A: Commutative Property of Addition
Answer:
Step-by-step explanation:
If
τ
1
and
τ
2
are two typologies on non-empty set
X
, then ………………. is topological space.
Answer:
2x + 3 = 9
Step-by-step explanation:
Three more than twice a number is nine
Twice a number would be 2x
where x is the number
Three more would be + 3
And is means equal sign or “=“
