<span>Since 360 is a multiple of 120, it is automatically the LCM of this problem.
</span>
Answer:
b-14 = 9
b = 23
Step-by-step explanation:
Add 14 to 9 to get b alone.
Answer:
f(-2)= -6
Step-by-step explanation:
Hope this helps :)
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86