First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
For the first one: 1.14
Second one: 3.66
<span>To find the area of a two dimensional triangle we multiply one half of the base width by the base height so lets start with finding the area of a two dimensional part of the triangular prism. </span>
Answer:
because when two negatives are together they can't add
Step-by-step explanation:
because when two negatives are together they can't add no matter if there's an addition sign
20, you just need to substitute the x value in the equation
(-2)2-7(-2)+10=
=20
