Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
= 
= 
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
Answer:
cef
Step-by-step explanation:
The answer to this question is 0.527
Given:
Charlie bought a new computer for $450 with his credit card.
He plans to pay the minimum payment of $25 per month.
To find:
The rate of change.
Solution:
Let y be the remaining amount of loan after x months.
Initial amount of loan = $450
Payment of one month = $25
Payment of x months = $25x
Now,
Remining amount = Initial amount of loan - Payment of x months
...(i)
The slope intercept form is
...(ii)
where, m is slope and b is y-intercept.
From (i) and (ii), we get
Therefore, the rate of change is -25 dollars.
Answer:
a8 = 0.004
Step-by-step explanation:
Q is abt a geometric series given by the eqn: an = a1*r^(n-1)
given a1 = 40000, r = 0.1
an = 40000*(0.1)^(n-1)
a8 = 40000*(0.1)^(8-1)
= 40000*(0.1)^7
= 0.004
