Anyone can help me with this
1 answer:
Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median =
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
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Coordinates of the given triangle ΔPQR P(1,-1), Q(3,-2), R(3,-4).
a) Let us discuss the rule for rotation of 90° clockwise about the origin.
If given coordinate is (h,k) is rotated 90° clockwise about the origin the position of rotated coordinate will be (k, -h).
x and y coordinates would switch their values and after switching x any values, the y value of the coordinates would reverse in sign.
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P'(-1,-1)
Q(3,-2) --> Q'( -2,-3)
R(3,-4) --> R'(-4,-3)
b) If given coordinate is (h,k), the coordinates after reflection across the x-axis would besome (h,-k). (Just change in the sign of y-coordinate).
So, the coordinates of rotated ΔPQR P(1,-1), Q(3,-2), R(3,-4) would become
P(1,-1) --> P"(1,1)
Q(3,-2) --> Q"( 3,2)
R(3,-4) --> R"(3,4)
