Anyone can help me with this
1 answer:
Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median =
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
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The image of circle A is missing, so i have attached it;
Answer:
x = 17
Step-by-step explanation:
In Δs EAB and EAD
We are told that;
∠BAE ≅ ∠DAE
AB = AD = AE
Now,
The Two triangles have two corresponding equal sides and the angles between them are equal, thus, we can say that the two triangles are congruent by SAS (Side Angle Side) postulate of congruence
By using the result of congruence, we can say that;
EB ≅ ED
We are given that;
EB = 3x - 24 and ED = x + 10
Thus,
3x - 24 = x + 10
∴ 3 x - 24 = x + 10
Add 24 to both sides to give;
3x = x + 34
Subtract x from both sides to give;
2x = 34
Divide both sides by 2 to give;
x = 17
