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Lina20 [59]
3 years ago
9

Anyone can help me with this

Mathematics
1 answer:
Leokris [45]3 years ago
8 0

Given:

The data values are

11, 12, 10, 7, 9, 18

To find:

The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.

Solution:

We have,

11, 12, 10, 7, 9, 18

Arrange the data values in ascending order.

7, 9, 10, 11, 12, 18

Divide the data in two equal parts.

(7, 9, 10), (11, 12, 18)

Divide each parenthesis in 2 equal parts.

(7), 9, (10), (11), 12, (18)

Now,

Median = \dfrac{10+11}{2}

            = \dfrac{21}{2}

            = 10.5

Lowest value = 7

Greatest value = 18

Lower quartile = 9

Upper quartile = 12

Interquartile range (IQR) = Upper quartile - Lower quartile

                                        = 12 - 9

                                        = 3

Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.

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Answer:

Step-by-step explanation:

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Martin is paid an hourly rate of d dollars per hour for the first 40 hours he works per week. He is paid one-and-a-half times hi
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Answer:

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Step-by-step explanation:

Given that:

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Hence,

40d + 10(1.5d) = 770 can be used to determine Martin's hourly pay.

5 0
2 years ago
Find x so that l || m. Show your work.
Hatshy [7]

Hello,

Answer:

x = 13

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6 0
1 year ago
Plz help<br> and explain
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To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.

We're given that the purple (smaller) square has a side length of x inches.
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Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.

The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.

Therefore
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8 0
3 years ago
Given vectors a and b, which operation does the green vector show? options: 2a + b
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6 0
3 years ago
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