Answer:
The rate charged by first mechanic per hour= x =$85
The rat charged by second mechanic per hour =y = $70
Step-by-step explanation:
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. Together they charged a total of $1900. What was the rate charged per hour by each mechanic if the sum of the two rates was $155 per hour?
Solution
Let
x= hourly rate of the first mechanic
y= hourly rate of the second mechanic
Derive two equations to solve for the two unknowns
10x + 15y = 1900 (1)
x + y = 155 (2)
From (2)
x + y = 155
x=155-y
Substitute x=155-y into (1)
10x + 15y = 1900
10(155-y) + 15y =1900
1550 -10y + 15y =1900
5y =1900-1550
5y=350
Divide both sides by 5
y= 70
Substitute y=70 into (2)
x + y = 155
x + (70) =155
x=155 - 70
= 85
x= 85
The rate charged by first mechanic per hour= x =$85
The rat charged by second mechanic per hour =y = $70
Answer is $782.10
1st year —2754 ÷ 0.27 = 743.58 2754 – 743.58 = 2010.42
2nd year— 2010.42 ÷ 0.27 = 542.81 2010.42 – 542.81 = 1467.61
3rd year — 1467.61 ÷ 0.27 = 396.25 1467.61 – 396.25 = 1071.36
4th year — 1071.36 ÷ 0.27 = 289.26 1071.36 – 289.26 = 782.10
Answer:
78 or -82
Step-by-step explanation:
-2+80=78
-2-80=-82
Answer:
30 miles
Step-by-step explanation:
Let d represent the distance to the island. The relation between time, speed, and distance is ...
time = distance/speed
so the total time for the round trip is ...
d/15 +d/10 = 5
Multiplying by 30, we get
2d +3d = 150
d = 150/5 = 30
The island was 30 miles from the harbor.
Answer: -3
f(0)=2•0-3
f(x)=-3