To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>
The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
If we equate this
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
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Answer:
11x
Step-by-step explanation:
u just add them regularly
X cannot be 6 or -2/5 because if they were the denominator would be zero
Answer:
Step-by-step explanation:
1/2 multiplied by (12 multiplied by 2)
1/2 (24)
= 12 inches grown + 23 inches
= 35 inches long
Answer:
108
Step-by-step explanation:
Limit as x approaches 9 of x^2 -81/sqrt of x - 3
First substitute x into the expression
= 9²-81/√9 - 3
= 81-81/3-3
= 0/0 (indeterminate)
Apply l'hospital rule
= lim x -> 9 d/dx(x²-81)/√x - 3
= lim x -> 9 2x/1/2√x
Substitute x = 9
= 2(9)/1/2√9
=18/1/(2(3)
=18 × 6/1
= 108
Hence the limit of the function is 108
