Let
be the number of students who eat cauliflower.
Therefore,
.
Let
be the total number of students surveyed.
Therefore, 
Thus, 

Now, for 90% confidence level, from the table we know that
.
The formula for the interval range of proportion of students is :

Plugging in the values we get:

Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).
7.5% of 225 is <span>16.875.
</span>
Answer:
1/45
Step-by-step explanation:
P(Y,Y) = 2/10 x 1/9 which is 1/45 simplified
The measure of angle 6 can be found by subtracting the measure of angle 13 from 90.
90-13 = 77