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Tju [1.3M]
3 years ago
11

Does anyone know this problem? Zneed ASAP!!!

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0
Y = |x| - 4 due to the fact it touches (0,4)
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Gill rolls a number cube 78 times. How many times can he expect to roll an odd number greater than 1?
bekas [8.4K]
Im assuming its just a regular number cube with 6 numbers 
there are only 2 odd numbers above 1 ( 3 and 5) 

so the ratio is 2/6 

you want to know how manny times (x) will you roll those numbers out of 78 roll 
the ratio is x/78 

multiply 

(2/6) = (x/78) 

cross multply to give you 6x= 156 and divide by 6 

<span>to give you x = 26 


</span>
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3 years ago
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5th Grade Math Help!​
3241004551 [841]

Answer:

C. 500

Step-by-step explanation:

1/10 of 5000 = 1/10 × 5000

= 500

4 0
4 years ago
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What do u get when u Simplify (5b)(-3a).
valentina_108 [34]
-15ba. just answered it
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Jon bought 1 2⁄3 pounds of green peppers and 3⁄5 pound of yellow peppers. How much more did the green peppers weigh than the yel
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Jon bought 1 and 7/10 more of green peppers than yellow 

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3 years ago
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Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In the formula, d is displac
OverLord2011 [107]

Answer:

2(d-vt)=-at^2

a=2(d-vt)/t^2

at^2=2(d-vt)

Step-by-step explanation:

Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is

displacement, v is final velocity, a is acceleration, and t is time.

Given the formula for calculating the displacement of a body as shown below;

d=vt - 1/2at^2

Where,

d = displacement

v = final velocity

a = acceleration

t = time

To make acceleration(a), the subject of the formula

Subtract vt from both sides of the equation

d=vt - 1/2at^2

d - vt=vt - vt - 1/2at^2

d - vt= -1/2at^2

2(d - vt) = -at^2

Divide both sides by t^2

2(d - vt) / t^2 = -at^2 / t^2

2(d - vt) / t^2 = -a

a= -2(d - vt) / t^2

a=2(vt - d) / t^2

2(vt-d)=at^2

4 0
3 years ago
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