Answer:
Part a) The distance on a map between Joseph's house and the airport is 2.53 inches
Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches
Step-by-step explanation:
Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles
Let
x-----> the distance on a map
1/9.5=x/24
x=24/9.5=2.53 inches
Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?
we know that
The scale of a map is 1 inch : 9.5 miles
so
using proportion
Find the distance on a map if the actual distance between airport to the restaurant is 16 miles
Let
x-----> the distance on a map
1/9.5=x/16
x=16/9.5=1.68 inches
The total distance on a map between Joseph's house and the restaurant is equal to
2.53 inches+1.68 inches=4.21 inches
Answer: B, D, and E
0.85L
or
L-0.15L
or
L(1-0.15)
or
Step-by-step explanation:
L is the number of hours Landen spent at the beach. Mateo spent 15% less time. This means he spent 85% of it. So 0.85 times L. We can also calculate it by subtracting the difference between the two kids. - 15%. 15% is 0.15L or . We subtract by L-0.15L or as . This fraction can simplify to
Steps to solve:
0.3x = 15
~Divide 0.3 to both sides
0.3x/0.3 = 15/0.3
~Simplify
x = 50
This is a vertical line so the slope is undefined.
The line passes through the point (50, 0) and there is no y-intercept since its a straight vertical line.
Best of Luck!
Answer:
Step-by-step explanation:
y = mx + b
y = -x/3 + b
1 = -2/3 + b
b = 5/3
y = -x/3 + 5/3