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Alik [6]
2 years ago
8

What is the value of the expression 4x-y/2y+z when x=3 and y=3

Mathematics
1 answer:
dimaraw [331]2 years ago
4 0

Answer:

14.5

Step-by-step explanation:

When solving this we need to use the substitution method. So let's substitute 3 for x and 3 for y.

4x - y / 2y + x

4 ( 3 ) - 3 / 2 (3)  + 3

12 - 3 / 6 + 3

Using the method PEMDAS we know to solve the parenthesis first.

12 - 3 / 2(3) + 3

12 - 3 / 6 + 3

Using the method again we know to divide before we add or subtract,

12 - 3 / 6 + 3

12 - 0.5 + 3

Then we subtract

12 - 0.5 = 11.5

Lastly, we add the remaining numbers

11.5 + 3 = 14.5

Hope this helps :)

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Write a 3-digit number that is divisible by both 3 and 4. Explain how you know this number is divisible by 3 and 4.
Alexeev081 [22]

Answer:

let us assume the 3 digit number be 984

To check weather the number is divisible by 3 and 4 then when should know the divisibility rule of 3 and 4.

A number is said to be divisible by 3 when the sum of each digit of the number is divisible by 3. Example 9+8+4 = 21 is divisible by 3 hence the number is divisible by 3.

A number is said to be divisible by 4 when the last two digit is divisible by 4 like 84 is divisible by 4 hence 984 is divisible by 4.

5 0
3 years ago
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This one is a doozy for me, need help please
Maksim231197 [3]

Answer:

The correct answer is B

Step-by-step explanation:

Kinda complicated to explain, if you need me to then comment and I'll do it

4 0
2 years ago
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Write the ordered pair that represents MP. Then find the magnitude of MP.
jarptica [38.1K]

Answer:

(23,-4):\sqrt{545} units

Step-by-step explanation:

We are given that M(-19,4)and P(4,0)

We have to find the ordered pair that represents MP and find the magnitude of MP.

MP=P-M

MP=(4,0)-(-19,4)=(4+19,0-4)

MP=(23,-4)

Magnitude of MP=\sqrt{(23)^2+(-4)^2}

Magnitude of MP=\sqrt{529+16}

Magnitude of MP=\sqrt{545} units

Hence, .option c is true.

Answer:c.(23,-4):\sqrt{545} units

5 0
2 years ago
Rationalize the denominator !!!
satela [25.4K]

Answer:

\frac{1\cdot \left(4+\sqrt{3}\right)}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}\\

1\cdot \left(4+\sqrt{3}\right)=4+\sqrt{3}

\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right) = 13

= \frac{4+\sqrt{3}}{13}

x = 4

y = 3

z = 13

4 0
1 year ago
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What is the mass (in grams) of 8.11×1026 CO2 molecules?
Kobotan [32]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>5</u><u>9</u><u>,</u><u>2</u><u>7</u><u>5</u><u>.</u><u>7</u><u>4</u><u> </u><u>grams</u>

Step-by-step explanation:

• Molecular mass of carbon dioxide

= (12 \times 1) + (16 \times 2) \\  = 12 + 32 \\  = 44 \: g

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

{ \sf{6.02 \times  {10}^{23}  \: molecules = 44 \: g }}\\  { \sf{8.11 \times  {10}^{26}  \: molecules =( \frac{8.11 \times  {10}^{26} }{6.02 \times  {10}^{23} }   \times 44) \: g}} \\  \\  = { \boxed{ \boxed{ \bf{59275.7 \:  \: g}}}}

6 0
3 years ago
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