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3 years ago

Which of the following is not a command for determining if MySQL is running on Linux (Ubuntu)?

Computers and Technology

1 answer:

laila [671]3 years ago

6 0

Answer:

Explanation:

The commands service, ps and systemctl, are different ways to find out if MySQL is running on Linux (Ubuntu), but there is not such a command called check to do so in Linux.

Different programs in Linux operating system are organized in processes, and they are all created for a specific purpose: running an application, starting a web browser, and so on.

Some other programs like the init program start and stop essential service processes and there are currently two major implementations in Linux distributions:

System V init (traditional implementation)
systemd (emerging standard for init).

The commands service and systemctl are related to System V init and systemd, respectively, and can list the status of a program.

Thus, the command service can list if MySQL is running on Linux using the piece of code in the question: sudo service mysql status.

Likewise, the command systemctl can activate and deactivate services, and, among many other functionalities, list the status of a program (like the one in the question: systemctl status mysql).

The command ps (process status) "displays information about a selection of the active processes" [ps man page]. The command has many options, and some are -e (select all processes) and -f (full-format listing). In this case, the command output is piped to grep (global regular expression print) command to find those processes mainly related to 'mysql'.

It is important to remember that command sudo (superuser do) permits a user to "execute a command as the superuser or another user" [sudo man page], since commands service and systemctl require privileges to be run, for security reasons.

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) Consider the array called myArray declared below that contains and negative integers. Write number of positive integers in the

grigory [225]

Answer:

#include <iostream>

using namespace std;

int main()

{

int arr[]={3,-9,9,33,-4,-5, 100,4,-23};

int pos;

int n=sizeof(arr)/sizeof(arr[0]);

for(int i=0;i<n;i++){

if(arr[i]>=0){

pos++;

}

cout<<"Number of positive integers is "<<pos<<endl;

return 0;

}

Explanation:

create the main function in the c++ programming and declare the array with the element. Then, store the size of array by using the formula:

int n=sizeof(arr)/sizeof(arr[0]);

after that, take a for loop for traversing the array and then check condition for positive element using if statement,

condition is array element greater than or equal to zero.

if condition true then increment the count by 1.

this process happen until the condition true

and finally print the count.

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3 years ago

Write a menu-based program in C++ for an input restricted dequeue using Linked List consist of

Natali5045456 [20]

Answer:

C++ With Examples

— Input-restricted Deque: In input-restricted, deletion can be done from ... getLast: Retrieves the last item in the queue. ... Now, we insert element 3 at the rear.

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3 years ago

Discuss the major differences in two approaches ofprogramming i.e. Object oriented programming and structuredprogramming.

Romashka-Z-Leto [24]

Answer:

Differences between Object Oriented Programming and Structured Programming

1. Structured programming focuses on process/logic then data while OOP(Object Oriented programming) focuses on data.

2.OOP supports Inheritance,Encapsulation,Abstraction,Polymorphism while structured programming does not supports these.

3.Structured programming follows top-down approach while OOP follows bottom-up approach.

4.OOP is more secured than structured programming because it supports Abstraction (data hiding).

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3 years ago

Suppose you have a 16-bit machine with a page size of 16B. Assume that any unsigned 16-bit integer can be a memory address. Also

irinina [24]

Answer:

2^11

Explanation:

Physical Memory Size = 32 KB = 32 x 2^10 B

Virtual Address space = 216 B

Page size is always equal to frame size.

Page size = 16 B. Therefore, Frame size = 16 B

If there is a restriction, the number of bits is calculated like this:

number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]

where

physical memory size = 32KB which is the restriction

n bit machine = frame size = 16

Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11

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4 years ago

Create pseudocode to compute the volume of a sphere. Use the formula: V= (4/3)* π r3 where π is equal to 3.1416 approximately, w

MA_775_DIABLO [31]

Answer:

In geometry, the area enclosed by a circle of radius r is πr2. Here the Greek letter π represents a constant, approximately equal to 3.14159, which is equal to the ratio of the circumference of any circle to its diameter.

Explanation:

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3 years ago

Read 2 more answers