Answer:
See below
Step-by-step explanation:
The measure of all the arcs can be obtained by using 'Central angle and its corresponding arc theorem'.
1. The measure of arc AD is
2. The measure of arc ABC is
3. The measure of arc ADB is
4. The measure of arc BD is ![\boxed {85}\degree](https://tex.z-dn.net/?f=%20%5Cboxed%20%7B85%7D%5Cdegree%20)
There is no answer for that or endless ur looking for the answer is 5x
The least common multiple of 10 and 7 is 1
Answer:
Consecutive Interior Angles Theorem
Step-by-step explanation:
The angles are both between the lines and on the same side of the transversal.
The count of the equilateral triangle is an illustration of areas
There are 150 small equilateral triangles in the regular hexagon
<h3>How to determine the number of
equilateral triangle </h3>
The side length of the hexagon is given as:
L = 5
The area of the hexagon is calculated as:
![A = \frac{3\sqrt 3}{2}L^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B3%5Csqrt%203%7D%7B2%7DL%5E2)
This gives
![A = \frac{3\sqrt 3}{2}* 5^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B3%5Csqrt%203%7D%7B2%7D%2A%205%5E2)
![A = \frac{75\sqrt 3}{2}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B75%5Csqrt%203%7D%7B2%7D)
The side length of the equilateral triangle is
l = 1
The area of the triangle is calculated as:
![a = \frac{\sqrt 3}{4}l^2](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5Csqrt%203%7D%7B4%7Dl%5E2)
So, we have:
![a = \frac{\sqrt 3}{4}*1^2](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5Csqrt%203%7D%7B4%7D%2A1%5E2)
![a = \frac{\sqrt 3}{4}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5Csqrt%203%7D%7B4%7D)
The number of equilateral triangles in the regular hexagon is then calculated as:
![n = \frac Aa](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%20Aa)
This gives
![n = \frac{75\sqrt 3}{2} \div \frac{\sqrt 3}4](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B75%5Csqrt%203%7D%7B2%7D%20%5Cdiv%20%5Cfrac%7B%5Csqrt%203%7D4)
So, we have:
![n = \frac{75}{2} \div \frac{1}4](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B75%7D%7B2%7D%20%5Cdiv%20%5Cfrac%7B1%7D4)
Rewrite as:
![n = \frac{75}{2} *\frac{4}1](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B75%7D%7B2%7D%20%2A%5Cfrac%7B4%7D1)
![n = 150](https://tex.z-dn.net/?f=n%20%3D%20150)
Hence, there are 150 small equilateral triangles in the regular hexagon
Read more about areas at:
brainly.com/question/24487155