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3 years ago

14

Ivan and kate live 42 miles apart. ivan leaves his house at 8:00 a.m. and bikes towards kate's house at a constant speed of 12 m

ph. kate leaves her house at 9:30 a.m. but bikes towards ivan at constant speed of 18 mph. at what time will they meet?

1 answer:

valentinak56 [21]3 years ago

7 0

Answer:

10:18am

Step-by-step explanation:

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Kate borrowed $400 from her friend she will repay this amount with 3 percent interest for one year. What is the total amount she

padilas [110]

400 + 3% simple interest= 400+400(.03)=$412 due at the end of the year. ☺☺☺☺

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3 years ago

What is the final price of a $50 pair of headphones with sales tax of 5%.

ikadub [295]

Answer:

$52.50

Step-by-step explanation:

$50+5%= $52.50

Hope this helps

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3 years ago

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blagie [28]

Answer:

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Step-by-step explanation:

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3 years ago

Find the length of chord AB. Assume the graph is scaled by ones. Give exact and

iVinArrow [24]

Answer: Choice C

exact length = sqrt(26) units

approximate length = 5.10 units

=======================================================

Work Shown:

We can use the distance formula.

A = (x1,y1) = (2,2)

B = (x2,y2) = (1,-3)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(2-1)^2 + (2-(-3))^2}\\\\d = \sqrt{(2-1)^2 + (2+3)^2}\\\\d = \sqrt{(1)^2 + (5)^2}\\\\d = \sqrt{1 + 25}\\\\d = \sqrt{26}\\\\d \approx 5.0990195\\\\d \approx 5.10\\\\$

The distance from A to B is exactly sqrt(26) units which approximates to 5.10 units. This distance represents the length of chord AB.

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3 years ago

What is the sum of first k+1 even numbers

Gekata [30.6K]

Answer:

$Sum = (k+1)(k+2)$

Step-by-step explanation:

Given

k + 1 even numbers

Required

Their sum

This question will be solved using the sum of nth term of an AP

$S_n = \frac{n}{2}(2a + (n - 1)d)$

Where

a = the first even number

$a = 2$

n = number of terms

$n =k +1$

d = difference between consecutive even numbers

$d = 2$

So, the expression becomes:

$Sum = \frac{k+1}{2}(2 * 2 + (k + 1 - 1) * 2)$

$Sum = \frac{k+1}{2}(2 * 2 + (k) * 2)$

$Sum = \frac{k+1}{2}(4 + 2k)$

$Sum = \frac{(k+1)(4 + 2k)}{2}$

Factorize 4 + 2k

$Sum = \frac{(k+1)*2*(2 + k)}{2}$

$Sum = (k+1)*(2 + k)$

$Sum = (k+1)*(k+2)$

$Sum = (k+1)(k+2)$

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3 years ago