Question

Solve the equation: 12=19-√3x-11

Answer 1

Step  1  :Isolate the square root on the left hand side :

     Original equation 
     12 = 19-√3x-11

     Isolate
     √3x-11 = -12+19

      Tidy up 
     √3x-11 = 7

Step  2  :Eliminate the radical on the left hand side :

     Raise both sides to the second power
     (√3x-11)2 = (7)2

     After squaring 
     3x-11 = 49

Step  3  :Solve the linear equation :

     Rearranged equation
      3x  -60 = 0

     Add  60  to both sides
      3x  = 60

     Divide both sides by 3
     A possible solution is :
     x = 20

Step  4  :Check that the solution is correct :

     Original equation, root isolated

     √3x-11 = 7

     Plug in 20 for  x 
      √3•(20)-11 = 7
      Simplify
      √49 = 7
     Solution is: 
      x = 20

One solution was found :                        x = 20

Answer 2

The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!