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yuradex [85]
4 years ago
12

Solve the equation: 12=19-√3x-11

Mathematics
2 answers:
blondinia [14]4 years ago
5 0
<span>Step  1  :</span>Isolate the square root on the left hand side :

     Original equation 
<span>     12 = 19-√3x-11

</span>     Isolate
<span>     √3x-11 = -12+19

</span>      Tidy up 
<span>     √3x-11 = 7

</span>

<span>Step  2  :</span>Eliminate the radical on the left hand side :

     Raise both sides to the second power
<span>     (√3x-11)2 = (7)2

</span>     After squaring 
<span>     3x-11 = 49

</span>

<span>Step  3  :</span>Solve the linear equation :

     Rearranged equation
<span>      3x  -60 = 0
</span>
     Add  60  to both sides
<span>      3x  = 60
</span>
     Divide both sides by 3
     A possible solution is :
<span>     x = 20
</span>

<span>Step  4  :</span>Check that the solution is correct :

     Original equation, root isolated


<span>     √3x-11 = 7

</span>     Plug in 20 for  x 
<span>      √3•(20)-11 = 7
</span>      Simplify
     <span> √49 = 7</span>
     Solution is: 
<span>      x = 20
</span>

One solution was found :                  <span>      x = 20

</span>
Alekssandra [29.7K]4 years ago
4 0
The answer is x=20. You isolate the square root. Eliminate the radical on the left handside. And then solve it!
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1 year ago
Which value of x is a solution to this equation?
Ilya [14]

Answer:

<u>Solve the equation:</u>

  • 2x² − 4x + 16 = 0
  • x² - 2x + 8 = 0
  • x² - 2x + 1 + 7 = 0
  • (x - 1)² + 7 = 0
  • (x - 1)² = -7

There is no solution as the square of the number can't be negative

----------------------------

<u>Note if the equation was 2x² - 4x - 16 = 0, the solution would be:</u>

  • 2x² - 4x -  16 = 0
  • x² - 2x - 8 = 0
  • x² - 2x + 1 = 9
  • (x - 1)² = 3²
  • x - 1 = ± 3
  • x = -2, x = 4

In this case x = -2 is the correct choice

3 0
3 years ago
Read 2 more answers
Can someone find F(12).<br> i really have no idea...<br> Please and thank you?
posledela

Answer: 909.03

Step-by-step explanation:

We know that the equation is an exponential function, it can be written as y=ab^x

100 &=a b^{6.5} \dots \mathrm{Equation \ 1} \\11 &= a b^{1} \\

\Rightarrow ab^1=11

\Rightarrow \frac{ab^1}{b}=\frac{11}{b};\quad \:b\ne \:0

\Rightarrow a=\frac{11}{b}

a = 11/b, substitute it in equation 1

100 &=a b^{6.5}

\Rightarrow 100=\left(\frac{11}{b}\right)b^{6.5}

\Rightarrow 100b=11b^\frac{11}{2}

\Rightarrow 11\sqrt{b^{11} } =100b

\Rightarrow \sqrt{b^{11} } =\frac{100}{11}}

\Rightarrow \sqrt{b^{11} } =\frac{100}{11}}

\Rightarrow {b^{11} } =\frac{10000}{121}}

\Rightarrow {b} =\frac{\sqrt[11]{10000 \cdot 11^9} }{11}

\Rightarrow {b} = 1.49379

a = 11/b

a = 11/(1.49379)

a = 7.36382

Equation: y = (7.36382)(1.49379)^x

Now plug in 12 for x:
\Rightarrow { \left(7.36382\right)\left(1.49379\right)^{12}

\Rightarrow 7.36382\cdot \:1.49379^{12}

\Rightarrow 7.36382\cdot \:123.44530\dots

\Rightarrow 909.03

Therefore, f(12) = 909.03 for the exponential function

6 0
2 years ago
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