All categories

2 years ago

What is the solution to the equation 3X + 27 = -2x + 18

Mathematics

2 answers:

Stolb23 [73]2 years ago

6 0

Answer:-9/5

Step-by-step explanation:

3x + 27 = -2x + 18

-27 -27

-3x = -2x - 9

+2x +2x

5x = -9

5x/5 = -9/5

x= -9/5

Anna11 [10]2 years ago

5 0

Answer:

-9/5 or -1.8

Step-by-step explanation:

3x+27=-2x+18 add 2x to both side

5x+27=18 minus 27 from both side

5x=-9 divide 5

x=-9/5, in decimal form=-1.8

You might be interested in

What table shows a proporioal relationship between x and y

katen-ka-za [31]

how can i help with the following problem if there are no tables

4 0

2 years ago

What is the median value of the data set shown on the line plot?<br><br> HELP ASAP

pochemuha

Answer:

Median: 6

Step-by-step explanation:

1,2,3,3,4,4,5,5,5,6,6,6,6,7,7,7,8,8,8,9,9,11

half of 22 (total numbers) is 11, on the 11th spot it is 6

8 0

2 years ago

Middle school students are going on a field trip. Adult volunteers are needed to accompany the students on the field trip. The t

Alecsey [184]

Answer:

I'm not sure I get the question.

Step-by-step explanation:

x + y = ???

I don't know what your questions means.

Maybe more context?

3 0

2 years ago

The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea

Archy [21]

Answer:

Step-by-step explanation:

Given data:

$\mu = 473$

standard deviation is $\sigma= 28$

As distribution is normal in shape and values are symmetrical

The standard deviation rule says that 95% of observation lies between the second standard deviation of the mean

so, approximately only 5% of observation lies outside the interval and normal shape is symmetric. hence approximately 0.15% of observation lies above the interval

$= \mu + 2\times \sigma$

$= 473 + 2\times 28 = 529$

almost 0.15% of students spent more amount is 529

6 0

3 years ago

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

4 0

2 years ago